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PI3546-00-LGIZ Datasheet(PDF) 29 Page - Vicor Corporation |
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PI3546-00-LGIZ Datasheet(HTML) 29 Page - Vicor Corporation |
29 / 37 page ![]() Cool-Power® Rev 1.3 vicorpower.com Page 29 of 37 02/2016 800 927.9474 PI354x-00 LGH Amplifier Small Signal Model A small signal model of the LGH amplifier is shown in Figure 60. The LGH amplifier consists of three distinct stages. The first is a wide bandwidth integrator stage, followed by a fixed gain level shift circuit. Finally, the level shift circuit drives a trans- conductance (TCA) amplifier with an open collector sink only output stage. Since the LGH output is internally connected to the output of the voltage error amplifier, the compensation components show up in the model and are used by both stages, depending on which one is in use. Only one stage should be in use at a time. When using LGH or if the LGH input rises above the internal reference, the voltage error amplifier acts as a 400uA current source pull up for the EAO pin. Figure 61 shows a small signal model of the modulator gain when using the application circuit shown in Figure 59 with two 3.4 V high current LED’s in series. RLED is the series combination of the AC resistance of each LED, which is 0.2 Ohms. Rshunt is used to sense the current through the LED string. It has a value of 0.050 Ohms in this case. The other component values were defined earlier and remain the same values. Equation (11) defines the transfer function of the modulator and Equation (12) defines the pole of transfer function. The transfer function of the LGH amplifier is defined in Equation (13). The open loop gain of Eint is 2500 and ELS = 4.4. Figure 60 — LGH Amplifier Small Signal Model Vlgh Rzi Eint Cint ELS GMlgh 400 u leao Chf Rzi Ccomp Rout Veao Figure 61 — Lighting Application Modulator Gain Model Rshunt Vout gMOD rEQ Cout RLED Veao Vlgh Fpled = = 1.2 kHz (12) 1 2 • π • ((RLED + Rshunt))//reQ) • C OUT Glgheao(s) = Eint (s) = • ELS • GMlgh • (13) Fphf = = 580 kHz (14) Chf + Ccomp 2 • π • (Rzi // R OUT) • Ccomp • Chf Gled(s) = gMOD • (rEQ • Rshunt)/((Rshunt + RLED + rEQ) + s (C OUT • rEQ • RLED+Rshunt • rEQ • COUT)) (11) R OUT + s (Rzi • Ccomp • ROUT) 1 + s • (Ccomp+Chf) + s2 • (Chf • Ccomp • Rzi) The integrator pole is determined by the external input resistor Rlgh and the internal Cint, which is 20 pF. Assuming Rlgh = 100 k and Eint = 2500: |
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