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LM4925 Datasheet(PDF) 12 Page - National Semiconductor (TI) |
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LM4925 Datasheet(HTML) 12 Page - National Semiconductor (TI) |
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12 / 15 page ![]() Application Information (Continued) filter that limits low frequency response. This value should be chosen based on needed frequency response and turn-on time. SELECTION OF INPUT CAPACITOR SIZE Amplifying the lowest audio frequencies requires a high value input coupling capacitor, Ci. A high value capacitor can be expensive and may compromise space efficiency in por- table designs. In many cases, however, the headphones used in portable systems have little ability to reproduce signals below 60Hz. Applications using headphones with this limited frequency response reap little improvement by using a high value input capacitor. In addition to system cost and size, turn on time is affected by the size of the input coupling capacitor Ci. A larger input coupling capacitor requires more charge to reach its quiescent DC voltage. This charge comes from the output via the feedback. Thus, by minimizing the capacitor size based on necessary low frequency re- sponse, turn-on time can be minimized. A small value of Ci (in the range of 0.1µF to 0.47µF), is recommended. AUDIO POWER AMPLIFIER DESIGN A 25mW/32 Ω Audio Amplifier Given: Power Output 10mWrms Load Impedance 16 Ω Input Level 0.4Vrms Input Impedance 20k Ω A designer must first choose a mode of operation (SE or BTL) and determine the minimum supply rail to obtain the specified output power. By extrapolating from the Output Power vs. Supply Voltage graphs in the Typical Performance Characteristics section, the supply rail can be easily found. 3.0V is a standard voltage in most applications, it is chosen for the supply rail. Extra supply voltage creates headroom that allows the LM4925to reproduce peak in excess of 10mW without producing audible distortion. At this time, the designer must make sure that the power supply choice along with the output impedance does not violate the conditions explained in the Power Dissipation section. Once the power dissipation equations have been addressed, the required gain can be determined from Equation 2. (4) From Equation 4, the minimum AV is 1; use A V = 1. Since the desired input impedance is 20k, and with a A V gain of 1, a ratio of 1:1 results from Equation 1 for R f to R. The values are chosen with R i = 20k and Rf = 20k. The final design step is to address the bandwidth requirements which must be stated as a pair of -3dB frequency points. Five times away from a -3dB point is 0.17dB down from passband response which is better than the required ± 0.25dB specified. f L = 100Hz/5 = 20Hz f H = 20kHz*5= 100kHz As stated in the External Components section, R i in con- junction with C i creates a C i ≥ 1/(2π * 20kΩ * 20Hz) = 0.397µF; use 0.39µF. The high frequency pole is determined by the product of the desired frequency pole, fH, and the differential gain, A V. With an AV V = 1 and fH = 100kHz, the resulting GBWP = 100kHz which is much smaller than the LM4925GBWP of 3MHz. This example displays that if a designer has a need to design an amplifier with higher differential gain, the LM4925can still be used without running into bandwidth limitations. www.national.com 12 |
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