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LT3758 Datasheet(PDF) 16 Page - Analog Devices |
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LT3758 Datasheet(HTML) 16 Page - Analog Devices |
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16 / 24 page ![]() LT8301 16 Rev. B For more information www.analog.com APPLICATIONS INFORMATION Step 2: Determine the Primary Inductance. Primary inductance for the transformer must be set above a minimum value to satisfy the minimum switch-off and switch-on time requirements: LPRI ≥ tOFF(MIN) •NPS • VOUT + VF ( ) ISW(MIN) LPRI ≥ tON(MIN) • VIN(MAX) ISW(MIN) tOFF(MIN) = 450ns tON(MIN) = 170ns ISW(MIN) = 290mA (typ) Example: LPRI ≥ 450ns•3•(5V +0.3V) 290mA = 25µH LPRI ≥ 170ns•32V 290mA = 19µH Most transformers specify primary inductance with a tol- erance of ±20%. With other component tolerance consid- ered, choose a transformer with its primary inductance 30% larger than the minimum values calculated above. LPRI = 40µH is then chosen in this example. Once the primary inductance has been determined, the maximum load switching frequency can be calculated as: fSW = 1 tON + tOFF = 1 LPRI •ISW VIN + LPRI •ISW NPS •(VOUT + VF) ISW = VOUT •IOUT •2 η• VIN •D Example: D = (5V +0.3V)•3 (5V +0.3V)•3+12V = 0.57 ISW = 5V •0.5A •2 0.85•12V •0.57 = 0.86A fSW =199kHz The transformer also needs to be rated for the correct saturation current level across line and load conditions. A saturation current rating larger than 2A is necessary to work with the LT8301. The 750313974 from Würth is chosen as the flyback transformer. Step 3: Choose the Output Diode. Two main criteria for choosing the output diode include forward current rating and reverse voltage rating. The maximum load requirement is a good first-order guess as the average current requirement for the output diode. A conservative metric is the maximum switch current limit multiplied by the turns ratio, IDIODE(MAX) = ISW(MAX) • NPS Example: IDIODE(MAX) = 4.125A Next calculate reverse voltage requirement using maxi- mum VIN: VREVERSE = VOUT + VIN(MAX) NPS Example: VREVERSE = 5V+ 32V 3 = 15.6V The CMSH5-20 (5A, 20V diode) from Central Semiconductor is chosen. |
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