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LM4927 Datasheet(PDF) 12 Page - National Semiconductor (TI) |
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LM4927 Datasheet(HTML) 12 Page - National Semiconductor (TI) |
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12 / 14 page ![]() Application Information (Continued) Tolerance R i1 R i2 V 02 -V01 I LOAD 20% 0.8R 1.2R -0.500V 62.5mA 10% 0.9R 1.1R -0.250V 31.25mA 5% 0.95R 1.05R -0.125V 15.63mA 1% 0.99R 1.01R -0.025V 3.125mA 0% R R 0 0 Since the same variations can have a significant effect on PSRR and CMRR performance, it is highly recommended that the input resistors be matched to 1% tolerance or better for best performance. AUDIO POWER AMPLIFIER DESIGN Design a 1W/8 Ω Audio Amplifier Given: Power Output 1Wrms Load Impedance 8 Ω Input Level 1Vrms Input Impedance 20k Ω Bandwidth 100Hz–20kHz ± 0.25dB A designer must first determine the minimum supply rail to obtain the specified output power. The supply rail can easily be found by extrapolating from the Output Power vs Supply Voltage graphs in the Typical Performance Characteris- tics section. A second way to determine the minimum supply rail is to calculate the required V OPEAK using Equation 7 and add the dropout voltages. Using this method, the minimum supply voltage is (Vopeak + (V DO TOP +(VDO BOT )), where V DO BOT and V DO TOP are extrapolated from the Dropout Voltage vs Supply Voltage curve in the Typical Perfor- mance Characteristics section. (7) Using the Output Power vs Supply Voltage graph for an 8 Ω load, the minimum supply rail just about 5V. Extra supply voltage creates headroom that allows the LM4927 to repro- duce peaks in excess of 1W without producing audible dis- tortion. At this time, the designer must make sure that the power supply choice along with the output impedance does not violate the conditions explained in the Power Dissipa- tion section. Once the power dissipation equations have been addressed, the required differential gain can be deter- mined from Equation 8. (8) R f /Ri =AVD From Equation 7, the minimum A VD is 2.83. A ratio of Rf to Ri of 2.83 gives R i = 14k Ω. The final design step is to address the bandwidth requirement which must be stated as a single -3dB frequency point. Five times away from a -3dB point is 0.17dB down from passband response which is better than the required ±0.25dB specified. f H = 20kHz*5= 100kHz The high frequency pole is determined by the product of the desired frequency pole, f H , and the differential gain, AVD . With a A VD = 2.83 and fH = 100kHz, the resulting GBWP = 150kHz which is much smaller than the LM4927 GBWP of 10MHz. This figure displays that if a designer has a need to design an amplifier with a higher differential gain, the LM4927 can still be used without running into bandwidth limitations. www.national.com 12 |
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