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LT8611 Datasheet(PDF) 19 Page - Linear Technology |
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LT8611 Datasheet(HTML) 19 Page - Linear Technology |
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19 / 28 page ![]() LTC3646/LTC3646-1 19 36461fc For more information www.linear.com/LTC3646 Thermal Considerations The LTC3646 requires the exposed package backplane metal (PGND) to be well soldered to the PC board to pro- vide good thermal contact. This gives the DFN and MSOP packages exceptional thermal properties, compared to other packages of similar size, making it difficult in normal operation to exceed the maximum junction temperature of the part. In many applications, the LTC3646 does not generate much heat due to its high efficiency. However, in applications in which the LTC3646 is running at a high ambient temperature, high input voltage, high switching frequency, and maximum output current, the heat dissi- pated may cause the part to exceed the maximum allowed junction temperature. If the junction temperature reaches approximately 175°C, both power switches will be turned off until temperature decreases approximately 10°C. Thermal analysis should always be performed by the user to ensure the LTC3646 does not exceed the maximum junction temperature. The temperature rise is given by: tRISE = PD θJA where PD is the power dissipated by the regulator and θJA is the thermal resistance from the junction of the die to the ambient. Consider the example in which an LTC3646IDE-1 is operating with IOUT = 1.0A, SVIN = 12V, f = 3MHz, VOUT = 1.8V, and a board temperature of 85°C. From the Typical Performance Characteristics section, the RDS(ON) of the top switch is found to be nominally 200mΩ while that of the bottom switch is nominally 120mΩ yielding an equivalent power MOSFET resistance RSW of: RDS(ON)TOP •1.8 12 + RDS(ON)BOT •10.2 12 = 132mΩ From the previous section, IGATECHG + IQ is ~15mA when f = 3MHz. Therefore, the total power dissipation due to resistive losses and LDO losses is: PD = IOUT2 • RSW + SVIN • (IGATECHG + IQ) PD = (1.0)2 • (0.132) + 12V • 15mA = 312mW and the transition loss is: PT = 1.0 • 122 • 10–10 • 3.0 • 106 = 43mW APPLICATIONS INFORMATION TheDFN4mm×3mmpackagejunction-to-ambientthermal resistance, θJA, is approximately 43°C/W. Therefore, the junction temperature of the regulator operating in a 85°C ambient temperature is approximately: TJ = (0.312 + 0.043) • 43 + 85 = 100°C which is below the specified maximum junction tempera- ture of 125°C. High input voltage, high frequency applications may cause the internal LDO to generate significant heat. The INTVCC current, which is dominated by the gate charge current, may be supplied by either the SVIN LDO or through the EXTVCC pin. When the voltage on the EXTVCC pin is less than4.5V,theVINLDOisenabled.Powerdissipationforthe IC in this case is highest and is equal to SVIN • IINTVCC. The gate charge current is dependent on operating frequency as discussed in the Efficiency Considerations section. For example, the LTC3646 INTVCC current is approximately 15mA at 3MHz operation. If VIN is at the 40V maximum, the loss in the on-chip LDO is: 40V • 0.015A = 0.60W In these situations it will be advantageous to bias the part through the EXTVCC pin if a suitable voltage source is available. When the voltage applied to EXTVCC rises above 4.5V (maximum 6.0V), the SVIN LDO is turned off and an internal switch between the EXTVCC and INTVCC pins is closed. This voltage is unregulated and so in this situation, INTVCC = EXTVCC. Using EXTVCC allows the control power to be derived from the output if the output voltage is between 4.5V and 6.0V during normal operation and from the SVIN LDO when the output is out of regulation (e.g., start-up, short-circuit). Significant efficiency and thermal gains can be realized by powering INTVCC from the output, since the power needed for the driver and control currents will be supplied from the buck converter instead of the internal linear regulator. For 4.5V to 6V regulator outputs, this means connecting the EXTVCC pin directly to VOUT. Tying the EXTVCC pin to a 5.5V supply reduces the dissipated power in the previous example from 0.60W to approximately: 5.5V • 0.015A = 82.5mW |
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