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AD8131ARMZ Datasheet(PDF) 16 Page - Analog Devices |
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AD8131ARMZ Datasheet(HTML) 16 Page - Analog Devices |
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16 / 20 page ![]() AD8131 Rev. B | Page 16 of 20 THEORY OF OPERATION The AD8131 differs from conventional op amps in that it has two outputs whose voltages move in opposite directions. Like an op amp, it relies on high open-loop gain and negative feedback to force these outputs to the desired voltages. The AD8131 behaves much like a standard voltage feedback op amp and makes it easy to perform single-ended-to-differential conversion, common-mode level-shifting, and amplification of differential signals. Previous discrete and integrated differential driver designs used two independent amplifiers and two independent feedback loops, one to control each of the outputs. When these circuits are driven from a single-ended source, the resulting outputs are typically not well balanced. Achieving a balanced output typically required exceptional matching of the amplifiers and feedback networks. DC common-mode level shifting has also been difficult with previous differential drivers. Level shifting required the use of a third amplifier and feedback loop to control the output common-mode level. Sometimes the third amplifier has also been used to attempt to correct an inherently unbalanced circuit. Excellent performance over a wide frequency range has proven difficult with this approach. The AD8131 uses two feedback loops to separately control the differential and common-mode output voltages. The differential feedback, set by internal resistors, controls only the differential output voltage. The common-mode feedback controls only the common-mode output voltage. This architecture makes it easy to arbitrarily set the common-mode output level. It is forced, by internal common-mode feedback, to be equal to the voltage applied to the VOCM input, without affecting the differential output voltage. The AD8131 architecture results in outputs that are very highly balanced over a wide frequency range without requiring external components or adjustments. The common-mode feedback loop forces the signal component of the output common-mode voltage to be zeroed. The result is nearly perfectly balanced differential outputs, of identical amplitude and exactly 180 degrees apart in phase. ANALYZING AN APPLICATION CIRCUIT The AD8131 uses high open-loop gain and negative feedback to force its differential and common-mode output voltages in such a way as to minimize the differential and common-mode error voltages. The differential error voltage is defined as the voltage between the differential inputs labeled +IN and −IN in Figure 39. For most purposes, this voltage can be assumed to be zero. Similarly, the difference between the actual output common-mode voltage and the voltage applied to VOCM can also be assumed to be zero. Starting from these two assumptions, any application circuit can be analyzed. CLOSED-LOOP GAIN The differential mode gain of the circuit in Figure 39 can be described by the following equation: 2 = = G F dm IN, dm OUT, R R V V where RF = 1.5 kΩ and RG = 750 Ω nominally. ESTIMATING THE OUTPUT NOISE VOLTAGE Similar to the case of a conventional op amp, the differential output errors (noise and offset voltages) can be estimated by multiplying the input referred terms, at +IN and −IN, by the circuit noise gain. The noise gain is defined as 3 1 = ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + = G F N R R G The total output referred noise for the AD8131, including the contributions of RF, RG, and op amp, is nominally 25 nV/√Hz at 20 MHz. CALCULATING THE INPUT IMPEDANCE OF AN APPLICATION CIRCUIT The effective input impedance of a circuit such as that in Figure 39, at +DIN and −DIN, will depend on whether the amplifier is being driven by a single-ended or differential signal source. For balanced differential input signals, the input impedance (RIN, dm) between the inputs (+DIN and −DIN) is Ω = × = k 5 . 1 2 , G dm IN R R In the case of a single-ended input signal (for example if −DIN is grounded and the input signal is applied to +DIN), the input impedance becomes () Ω = ⎟⎟ ⎟ ⎟ ⎟ ⎠ ⎞ ⎜⎜ ⎜ ⎜ ⎜ ⎝ ⎛ + × − = k 125 . 1 2 1 , F G F G dm IN R R R R R The input impedance is effectively higher than it would be for a conventional op amp connected as an inverter because a fraction of the differential output voltage appears at the inputs as a common-mode signal, partially bootstrapping the voltage across the input resistor RG. |
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