7540 datasheet(348/366 Pages) RENESAS

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Addressing mode

Symbol

Function

Details

IMP

IMM

BIT, A

BIT, ZP

OP n# OP n# OP n# OP n# OP n#

OP n

3-126

REJ09B0018-0200Z

Rev.2.00

Jun 21, 2004

APPENDIX

7540 Group

3.7 Machine instructions

This instruction subtracts one from the current

contents of X.

This instruction subtracts one from the current

contents of Y.

This instruction divides the 16-bit data in

M(zz+(X)) (low-order byte) and M(zz+(X)+1)

(high-order byte) by the contents of A. The

quotient is stored in A and the one's comple-

ment of the remainder is pushed onto the stack.

When T = 0, this instruction transfers the con-

tents of the M and A to the ALU which

performs a bit-wise Exclusive OR, and stores

the result in A.

When T = 1, the contents of M(X) and M are

transferred to the ALU, which performs a bit-

wise Exclusive OR and stores the results in

M(X). The contents of A remain unchanged,

but status flags are changed.

M(X) represents the contents of memory

where is indicated by X.

This instruction adds one to the contents of A

or M.

This instruction adds one to the contents of X.

This instruction adds one to the contents of Y.

This instruction jumps to the address desig-

nated by the following three addressing

modes:

Absolute

Indirect Absolute

Zero Page Indirect Absolute

This instruction stores the contents of the PC

in the stack, then jumps to the address desig-

nated by the following addressing modes:

Absolute

Special Page

Zero Page Indirect Absolute

When T = 0, this instruction transfers the con-

tents of M to A.

When T = 1, this instruction transfers the con-

tents of M to (M(X)). The contents of A remain

unchanged, but status flags are changed.

M(X) represents the contents of memory

where is indicated by X.

This instruction loads the immediate value in

This instruction loads the contents of M in X.

This instruction loads the contents of M in Y.

DEX

DEY

DIV

EOR

(Note 1)

INC

INX

INY

JMP

JSR

LDA

(Note 2)

LDM

LDX

LDY

← X – 1

← Y – 1

← (M(zz + X + 1),

M(zz + X )) / A

M(S)

← one's comple-

ment of Remainder

← S – 1

When T = 0

← A V– M

When T = 1

M(X)

← M(X) V– M

← A + 1 or

← M + 1

← X + 1

← Y + 1

If addressing mode is ABS

PCL

← ADL

PCH

← ADH

If addressing mode is IND

PCL

← M (ADH, ADL)

PCH

← M (ADH, ADL + 1)

If addressing mode is ZP, IND

PCL

← M(00, ADL)

PCH

← M(00, ADL + 1)

M(S)

← PCH

← S – 1

M(S)

← PCL

← S – 1

After executing the above,

if addressing mode is ABS,

PCL

← ADL

PCH

← ADH

if addressing mode is SP,

PCL

← ADL

PCH

← FF

If addressing mode is ZP, IND,

PCL

← M(00, ADL)

PCH

← M(00, ADL + 1)

When T = 0

← M

When T = 1

M(X)

← M

← nn

← M

3A 21

49 22

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