7540 datasheet(346/366 Pages) RENESAS

346 / 366 page

Addressing mode

Symbol

Function

Details

IMP

IMM

BIT, A

BIT, ZP

OP n# OP n# OP n# OP n# OP n#

OP n

3-124

REJ09B0018-0200Z

Rev.2.00

Jun 21, 2004

APPENDIX

7540 Group

3.7 Machine instructions

This instruction takes a branch to the ap-

pointed address if N is 0. The branch address

is specified by a relative address. If N is 1, the

next instruction is executed.

This instruction branches to the appointed ad-

dress. The branch address is specified by a

relative address.

When the BRK instruction is executed, the

CPU pushes the current PC contents onto the

stack. The BADRS designated in the interrupt

vector table is stored into the PC.

This instruction takes a branch to the ap-

pointed address if V is 0. The branch address

is specified by a relative address. If V is 1, the

next instruction is executed.

This instruction takes a branch to the ap-

pointed address when V is 1. The branch

address is specified by a relative address.

When V is 0, the next instruction is executed.

This instruction clears the designated bit i of A

or M.

This instruction clears C.

This instruction clears D.

This instruction clears I.

This instruction clears T.

This instruction clears V.

When T = 0, this instruction subtracts the con-

tents of M from the contents of A. The result is

not stored and the contents of A or M are not

modified.

When T = 1, the CMP subtracts the contents

of M from the contents of M(X). The result is

not stored and the contents of X, M, and A are

not modified.

M(X) represents the contents of memory

where is indicated by X.

This instruction takes the one’s complement of

the contents of M and stores the result in M.

This instruction subtracts the contents of M

from the contents of X. The result is not stored

and the contents of X and M are not modified.

This instruction subtracts the contents of M

from the contents of Y. The result is not stored

and the contents of Y and M are not modified.

This instruction subtracts 1 from the contents

of A or M.

BPL

(Note 4)

BRA

BRK

BVC

(Note 4)

BVS

(Note 4)

CLB

CLC

CLD

CLI

CLT

CLV

CMP

(Note 3)

COM

CPX

CPY

DEC

N = 0?

← PC ± offset

← 1

(PC)

← (PC) + 2

M(S)

← PCH

← S – 1

M(S)

← PCL

← S – 1

M(S)

← PS

← S – 1

← 1

PCL

← ADL

PCH

← ADH

V = 0?

V = 1?

Ai or Mi

← 0

When T = 0

A – M

When T = 1

M(X) – M

← M

X – M

Y – M

← A – 1 or

← M – 1

1A 2

20i

00 7

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