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LT3682 Datasheet(PDF) 19 Page - Linear Technology |
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LT3682 Datasheet(HTML) 19 Page - Linear Technology |
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19 / 24 page ![]() LT3682 19 3682f APPLICATIONS INFORMATION cases the discharged output capacitor will present a load to the switcher, which will allow it to start. The plots show the worst-case situation where VIN is ramping very slowly. For lower start-up voltage, the boost diode can be tied to VIN; however, this restricts the input range to one-half of the absolute maximum rating of the BOOST pin. At light loads, the inductor current becomes discontinuous and the effective duty cycle can be very high. This reduces the minimum input voltage to approximately 300mV above VOUT. At higher load currents, the inductor current is continuous and the duty cycle is limited by the maximum duty cycle of the LT3682, requiring a higher input voltage to maintain regulation. Soft-Start The RUN/SS pin can be used to soft-start the LT3682, reducing the maximum input current during start-up. The RUN/SS pin is driven through an external RC network to create a voltage ramp at this pin. Figure 7 shows the startup and shut-down waveforms with the soft-start circuit. By choosing a large RC time constant, the peak start-up current can be reduced to the current that is required to regulate the output, with no overshoot. Choose the value of the resistor so that it can supply 20μA when the RUN/SS pin reaches 2.5V. 5ms/DIV VRUN/SS 5V/DIV VOUT 5V/DIV IL 1A/DIV VRUN 5V/DIV 3682 F07 RUN/SS RUN GND 15k 0.22μF Figure 7. To Soft-Start the LT3682, Add a Resistor and Capacitor to the RUN/SS Pin LOAD CURRENT (mA) 1 4.5 5 5.5 1000 3.5 4 3 2.5 2 10 100 10 100 6 LOAD CURRENT(mA) 3682 F06 1 6 6.5 7 7.5 1000 4.5 4 5.5 5 3.5 2.5 3 2 8 TO RUN TO START (WORST CASE) VOUT = 3.3V TA = 25˚C L = 10μH f = 800kHz TO START (WORST CASE) TO RUN VOUT = 5V TA = 25˚C L = 10μH f = 800kHz Figure 6. The Minimum Input Voltage Depends on Output Voltage, Load Current and Boost Circuit is already in regulation, then the boost capacitor may not be fully charged. Because the boost capacitor is charged with the energy stored in the inductor, the circuit will rely on some minimum load current to get the boost circuit running properly. This minimum load will depend on input and output voltages, and on the arrangement of the boost circuit. The minimum load generally goes to zero once the circuit has started. Figure 6 shows a plot of minimum load to start and to run as a function of input voltage. In many |
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