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AD623 Datasheet(PDF) 18 Page - Analog Devices |
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AD623 Datasheet(HTML) 18 Page - Analog Devices |
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18 / 20 page ![]() AD8428 Data Sheet Rev. A | Page 18 of 20 APPLICATIONS INFORMATION The classic 3-op-amp topology used for instrumentation amplifiers typically places all the gain in the first stage and subtracts the common-mode signals only in the second stage. When operated at high gain, any amplifier is sensitive to large interfering signals that can saturate it, thus making it impossible to recover the signal of interest. The AD8428 splits the total gain of 2000 into two stages: 200 in the preamplification stage and 10 in the subtractor stage. Reducing the gain of the first stage helps to increase the common-mode range vs. differential signal range by avoiding saturation of the preamps. –15 –10 –5 0 5 10 15 –15 –10 –5 0 5 10 15 OUTPUT VOLTAGE (V) SINGLE STAGE GAIN, G = 2000 AD8428 Figure 46. AD8428 vs. Single Stage Gain Topology, G = 2000 In addition, filtering between stages can help to attenuate signals before they reach the second amplification stage. This filtering helps to prevent saturation of the second stage amplifier as long as the signals are located in frequencies other than the signal of interest. EFFECT OF PASSIVE NETWORK ACROSS THE FILTER TERMINALS The AD8428 filter terminals allow access between the two amplification stages. Adding a passive network between the two terminals can shape the transfer function over the frequency of the amplifier. The general expression for the transfer function is represented by Equation 1. 6000 2000 + × = Z(s) Z(s) G(s) (1) where Z(s) is the frequency dependent impedance of the network across the filter terminals. CIRCUITS USING THE FILTER TERMINALS Setting the Amplifier to Different Gains In its simplest form, the transfer function equation (Equation 1) implies that the AD8428 can be configured for gains lower than 2000. This can be achieved by attaching a resistor across the filter pins. Unlike the gain configuration of traditional instrumentation amplifiers, this resistor attenuates the signal that was previously amplified by the initial gain of 200. Because this resistor appears inside the feedback of the subtractor stage, it modifies the gain of the subtractor as well. The total gain formula is a simplified version of the transfer function equation (Equation 1). 6000 2000 + × = G G R R G (2) The RG unit is in ohms. The resistor value required to obtain the desired gain can be calculated using the following formula: G G R G − × = 2000 6000 The AD8428 defaults to G = 2000 when no gain resistor is used. When setting the amplifier to a different gain, the absolute gain accuracy is only 10%. In addition, the temperature mismatch of the external gain resistor increases the gain drift of the instrumen- tation amplifier. Gain error and gain drift are at a guaranteed minimum when a gain resistor is not used. For applications that require accuracy at different gains, low noise, and wide bandwidth, the AD8429 should be considered. Low-Pass Filter To help limit undesired differential signals, a first-order, low-pass filter can be implemented by adding a capacitor across the filter terminals of the AD8428, as shown in Figure 47. +IN –IN + – AD8428 OUT CF +FIL –FIL Figure 47. Differential Low-Pass Filter This single-pole filter limits the signal bandwidth, as shown in the following equation: F C C f ) k 6 ( 2 1 Ω π = The 6 kΩ factor comes from the internal resistor values. The tolerance of these resistors is 10%; therefore, using capacitors with a tolerance better than 5% does not provide a significant improvement on the absolute tolerance of the cutoff frequency. Limiting the bandwidth of the amplifier also helps to minimize the amount of out-of-band noise present at the output. Note that filtering common-mode signals by adding a capacitor on each filter terminal to ground degrades the performance of the amplifier. This practice is generally discouraged because it degrades CMRR performance. In addition, filtering common- mode signals has little effect on preventing the saturation of the internal nodes. On the contrary, the load added to the preamplifiers causes them to saturate with even smaller common-mode signals. |
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