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SLTS027B Datasheet(PDF) 3 Page - Texas Instruments |
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SLTS027B Datasheet(HTML) 3 Page - Texas Instruments |
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3 / 6 page ![]() Application Notes For technical support and more information, see inside back cover or visit www.ti.com PT5060 Series Adjusting the Output Voltage of the PT5060 Dual-Output Boost Converter Series The dual output voltage of the PT5060 series modules can be adjusted higher or lower than the factory pre-set voltage with the addition of a single external resistor. Table 1 gives the applicable adjustment range for each model in the series as Va (min) and Va (max). Adjust Up: An increase in the output voltage is obtained by adding a resistor R2, between pin 11 (Vo adj) and pins 2, 6, or 7 (GND). Adjust Down: Add a resistor (R1), between pin 11 (Vo adj) and pins 8, 9 or 10 (Vo1). Refer to Figure 1 and Table 2 for both the placement and value of the required resistor, either (R1) or R2 as appropriate. Notes: 1. Both the positive and negative voltage outputs from the ISR are adjusted simultaneously. 2. Use only a single 1% resistor in either the (R1) or R2 location. Place the resistor as close to the ISR as possible. 3. Never connect capacitors from Vo adj to either GND or Vo. Any capacitance added to the Vo adjust pin will affect the stability of the ISR. 4. An increase in the output voltage must be accompanied by a corresponding reduction in the specified maximum current at each output. For Vo1 and –Vo2, the revised maximum output current must be reduced to the equivalent of 6 watts and 3 watts respectively. i.e. Io1 (max) = 6 Adc Va and Io2 (max) = 3 Adc, Va where Va is the adjusted output voltage. 5. Adjustments to the output voltage will also limit the maximum input voltage that can be applied to the ISR. The maximum input voltage that may be applied is limited to (Vo – 1)Vdc or 14Vdc, whichever is less. Table 1 PT5060 ADJUSTMENT AND FORMULA PARAMETERS Series Pt # PT5061 PT5062 Vo (nom) ±12.0V ±15.0V Va (min) ± 7.5V ± 7.5V Va (max) ±14.0V ±20.0V The values of (R1) [adjust down], and R2 [adjust up], can also be calculated using the following formulas. 3.65 (Va – 2.5 ) (R1) = (Vo – Va) - 0.1 kΩ 9.125 - 0.1 kΩ R2 = Va - Vo Where: Vo = Original output voltage Va = Adjusted output voltage Figure 1 Table 2 PT5060 ADJUSTMENT RESISTOR VALUES Series Pt # PT5061 PT5062 Current 0.5/0.25Adc 0.4/0.2Adc Vo(nom) ±12.0Vdc ±15.0Vdc Va(req’d) 7.0 7.5 (4.0)k Ω Ω Ω Ω Ω (2.3)k Ω Ω Ω Ω Ω 8.0 (4.9)k Ω Ω Ω Ω Ω (2.8)k Ω Ω Ω Ω Ω 8.5 (6.2)k Ω Ω Ω Ω Ω (3.3)k Ω Ω Ω Ω Ω 9.0 (7.8)k Ω Ω Ω Ω Ω (3.9)k Ω Ω Ω Ω Ω 9.5 (10.1)k Ω Ω Ω Ω Ω (4.6)k Ω Ω Ω Ω Ω 10.0 (13.6)k Ω Ω Ω Ω Ω (5.4)k Ω Ω Ω Ω Ω 10.5 (19.4)k Ω Ω Ω Ω Ω (6.4)k Ω Ω Ω Ω Ω 11.0 (30.9)k Ω Ω Ω Ω Ω (7.7)k Ω Ω Ω Ω Ω 11.5 (65.6)k Ω Ω Ω Ω Ω (9.3)k Ω Ω Ω Ω Ω 12.0 (11.5)k Ω Ω Ω Ω Ω 12.5 18.2k Ω Ω Ω Ω Ω (14.5)k Ω Ω Ω Ω Ω 13.0 9.0k Ω Ω Ω Ω Ω (19.1)k Ω Ω Ω Ω Ω 13.5 6.0k Ω Ω Ω Ω Ω (26.7)k Ω Ω Ω Ω Ω 14.0 4.5k Ω Ω Ω Ω Ω (41.9)k Ω Ω Ω Ω Ω 14.5 (87.5)k Ω Ω Ω Ω Ω 15.0 15.5 18.2k Ω Ω Ω Ω Ω 16.0 9.0k Ω Ω Ω Ω Ω 16.5 6.0k Ω Ω Ω Ω Ω 17.0 4.5k Ω Ω Ω Ω Ω 17.5 3.6k Ω Ω Ω Ω Ω 18.0 2.9k Ω Ω Ω Ω Ω 18.5 2.5k Ω Ω Ω Ω Ω 19.0 2.2k Ω Ω Ω Ω Ω 19.5 1.9k Ω Ω Ω Ω Ω 20.0 1.7k Ω Ω Ω Ω Ω R1 = (Blue) R2 = Black C out 100 µF + R 2 Adjust Up (R 1) Adj Down – Vo 2 COM V in COM +Vo 1 PT5060 1 2,6,7 3,4,5 Vin – Vo 2 GND 11 Vo(adj) 8,9,10 +Vo 1 |
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