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AD8017 Datasheet(PDF) 13 Page - Analog Devices |
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AD8017 Datasheet(HTML) 13 Page - Analog Devices |
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13 / 17 page ![]() AD8017 –12– REV. C APPLICATIONS Output Power Characteristics as Applied to ADSL Signals The AD8017 was designed to provide both relatively high cur- rent and voltage output capability. TPCs 12 and 15 quantify the ac load current versus distortion of the device at loads of 100 Ω and 25 Ω at 1 MHz. Using approximately –50 dBc as the worst case distortion limit, the AD8017 exhibits acceptable linearity to within approximately 1.4 V of either supply rail (12 V or ± 6 V) while simultaneously providing 200 mA of load current. These levels are achieved at only 7 mA of quiescent current for each amplifier. ADSL applications require signal line powers of 13 dBm that can randomly peak to an instantaneous power (or V × I product) of 28.5 dBm. This equates to peak-to-rms voltage ratio of 5.3- to-1. Using a 1:2 transformer in the ADSL circuit illustrated below and 100 Ω as the line resistance, a peak voltage of 4.2 V at a peak current of 168 mA will be required from the line driver output (see Table I). See detailed application below. A higher turns ratio transformer can be used to reduce the primary out- put voltage swing of the amplifier (for devices that do not have the voltage swing, but do have the current drive capability). However, this requires more than an equivalent increase in current due to the added I × R losses from the transformer for the same receiver power. Generally this will result in added distortion. Table I below shows the ADSL ac current and volt- ages required for both a 1:1 and 1:2 transformer turns ratio. VIN 1k 1k 0.1 F 0.1 F 8 2 3 1 7 5 6 4.7V 4.7V VOUT 1:2 12V 1k 0.1 F 169 169 4 1k 1 F 1 F 0.1 F 10 F 12.5 12.5 100 AD8017 50 EFFECTIVE LOAD Figure 7. Single 12 V Supply ADSL Remote Terminal Transmitter Table I. DSL Drive Amplifier Requirements for Various Combinations of Line Power, Line Impedance, and Turn Ratios Line Insertion Line Turns Crest Reflected Per Amp Peak Per Amplifier Peak Current Power Loss Load Ratio Factor Impedance R1 = R2 Voltage Voltage Output Output 13 dBm 1 dB 100 Ω 1:1 5.3 100 Ω 50 Ω 1.585 V rms 8.4 V peak 84 mA 13 dBm 1 dB 100 Ω 1:2 5.3 25 Ω 12.5 Ω 0.792 V rms 4.2 V peak 168 mA Single 12 V Supply ADSL Remote Terminal (RT) Transmitter For consumer use, it is desirable to create an ADSL modem that can be a plug-in accessory for a PC. In such an application, the circuit should dissipate a minimum of power, yet still meet the ADSL specification. The circuit in Figure 7 shows a single 12 V supply circuit that uses the AD8017 as a remote terminal transmitter. This supply voltage is readily available on the PCI connector of PCs. The circuit configures each half of the AD8017 as an inverter with a gain of about six. Both of the amplifier circuits are ac coupled at both the inputs and the outputs. This makes the dc levels of the circuit independent of the other dc levels of the signal chain. The inputs will generally be driven by the output of an active filter, which has a low output impedance. Thus there will be a minimum of loading of the source caused by the 169 Ω input impedance in the pass band. The output will require a 1:2 step- up transformer to drive a 100 Ω line. The reflected impedance back to the primary will be 25 Ω. With 25 Ω of series termina- tion added (12.5 Ω in each output), the effective load that the differential amplifier outputs will drive is 50 Ω. The input and output ac coupling provides two high pass cir- cuits. The inputs are formed by the 0.1 µF capacitor and the 169 Ω resistor, which provides a break frequency of about 9.4 kHz. The two 1 µF capacitors in the output along with the 50 Ω effective load provides a 6.4 kHz break frequency in the output side. Both of these circuits want to reject the Plain Old Telephone System (POTS) band (dc to 4 kHz) while passing the ADSL upstream band, which starts at about 20 kHz. The positive inputs must be biased at midsupply, which is nomi- nally 6 V. This will maintain the maximum dynamic range of the output in each direction, regardless of the tolerance of the supply. The inverting configuration was chosen as this requires a steady dc current from this supply, as opposed to the signal- dependent current that would be required in a noninverting configuration. Several options were studied for creating this supply. A voltage regulator could be used, but there are several disad- vantages. The first is that this will not track the middle of the supplies as it will always have an output that is a fixed voltage from ground. This also requires an additional active component that will impact the cost of the total solution. A two-resistor divider could also be used. There is a tradeoff required here in the selection of the value of the resistors. As the resistors become smaller, the amount of power that they will dissipate will increase. For two 1 k Ω resistors, the power dissi- pation in this circuit would be 72 mW. Thus, in order to keep this power to a minimum, it is desirable to make the resistors as large as possible. |
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