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LM2695 Datasheet(PDF) 11 Page - Texas Instruments

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Part # LM2695
Description  LM2695 High Voltage (30V, 1.25A) Step Down Switching Regulator
PDF  21 Pages
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Manufacturer  TI [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI - Texas Instruments

LM2695 Datasheet(HTML) 11 Page - Texas Instruments

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ESR(min) =
25 mV x (R1 + R2)
R2 x IOR(min)
L1 =
VOUT x (VIN - VOUT)
IOR x FS x VIN
RON
200 ns x VIN(MAX)
t
1.3 x 10
-10
LM2695
www.ti.com
SNVS413A – JANUARY 2006 – REVISED APRIL 2013
APPLICATIONS INFORMATION
EXTERNAL COMPONENTS
The following guidelines can be used to select the external components.
R1 and R2: The ratio of these resistors is calculated from:
R1/R2 = (VOUT/2.5V) - 1
(9)
R1 and R2 should be chosen from standard value resistors in the range of 1.0 k
Ω - 10 kΩ which satisfy the
above ratio.
RON: The minimum value for RON is calculated from:
(10)
Equation 1 can be used to select RON if a specific frequency is desired as long as the above limitation is met.
L1: The main parameter affected by the inductor is the output current ripple amplitude (IOR). The limits for IOR
must be determined at both the minimum and maximum nominal load currents.
a) If the maximum load current is less than the current limit threshold (1.25A), the minimum load current is used
to determine the maximum allowable ripple. To maintain continuous conduction mode the lower peak should not
reach 0 mA. For this case, the maximum ripple current is:
IOR(MAX1) = 2 x IO(min)
(11)
The ripple calculated in Equation 11 is then used in the following equation:
where
•
VIN is the maximum input voltage
•
Fs is determined from Equation 1
(12)
This provides a minimum value for L1. The next larger standard value should be used, and L1 should be rated
for the IPK current level.
b) If the maximum load current is greater than the current limit threshold (1.25A), the LM2695 ensures the lower
peak reaches 1.25A each cycle, requiring that IOR be at least twice the difference. The upper peak, however,
must not exceed 2A. For this case, the ripple limits are:
IOR(MAX2) = 2 x (2A - IO(max))
(13)
and
IOR(MIN1) = 2 x (IO(max) - 1.25A)
(14)
The lesser of Equation 13 and Equation 14 is then used in Equation 12. If IOR(MAX2) is used, the maximum VIN is
used in Equation 12. The next larger value should then be used for L1. If IOR(MIN1) is used, the minimum VIN is
used in Equation 12. The next smaller value should then be used for L1. L1 must be rated for the peak value of
the current waveform (IPK in Figure 8).
C3: The capacitor at the VCC output provides not only noise filtering and stability, but also prevents false
triggering of the VCC UVLO at the buck switch on/off transitions. For this reason, C3 should be no smaller than
0.1 µF, and should be a good quality, low ESR, ceramic capacitor.
C2, and R3: Since the LM2695 requires a minimum of 25 mVp-p of ripple at the FB pin for proper operation, the
required ripple at VOUT1 is increased by R1 and R2. This necessary ripple is created by the inductor ripple current
acting on C2’s ESR + R3. The minimum ripple current is calculated using Equation 12, rearranged to solve for
IOR at minimum VIN. The minimum ESR for C2 is then equal to:
(15)
Copyright © 2006–2013, Texas Instruments Incorporated
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