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CLC5802IM Datasheet(PDF) 10 Page - National Semiconductor (TI) |
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CLC5802IM Datasheet(HTML) 10 Page - National Semiconductor (TI) |
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10 / 12 page ![]() Application Information (Continued) A resistive divider made from the 143 Ω and 60.4Ω resistors was chosen to reduce the loop-gain and stabilize the net- work. The CLC5802 composite integrator provides integra- tion over five decades of operation. R and C set the integra- tor’s gain. Figure 4 shows the frequency and phase response of the circuit in Figure 3 with R = 44.2 Ω and C = 360pF. K: R2/(R1 + R2) A 0: Op amp low Frequency open loop gain Positive Peak Detector The CLC5802’s dual amplifiers can be used to implement a unity-gain peak detector circuit as shown in Figure 5. The acquisition speed of this circuit is limited by the dynamic resistance of the diode when charging C hold. A plot of the cir- cuit’s performance is shown in Figure 6 with a 1MHz sinusoi- dal input. A current source, built around Q1, provides the necessary bias current for the second amplifier and prevents saturation when power is applied. The resistor, R, closes the loop while diode D 2 prevents negative saturation when VIN is less than V C. A MOS-type switch (not shown) can be used to reset the capacitor’s voltage. The maximum speed of detection is limited by the delay of the op amp and the diodes. The use of Schottky diodes will provide faster response. Adjustable or Bandpass Equalizer A “boost” equalizer can be made with the CLC5802 by sum- ming a bandpass response with the input signal, as shown in Figure 7. The overall transfer function is shown in Equation (3). (3) To build a boost circuit, use the design Equation 4 and 5. (4) (5) Select R 2 and C using Equation (4). Use reasonable values for high frequency circuits - R 2 between 10Ω and 5kΩ, C be- tween 10pF and 2000pF. Use Equation (5) to determine the parallel combination of R a and Rb. Select Ra and Rb by ei- ther the 10 Ω to 5kΩ criteria or by other requirements based on the impedance V IN is capable of driving. Finish the design by determining the value of K from Equation (6). DS101341-29 FIGURE 4. DS101341-30 FIGURE 5. DS101341-31 FIGURE 6. DS101341-32 FIGURE 7. www.national.com 10 |
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