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OPA820ID Datasheet(PDF) 13 Page - Texas Instruments |
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OPA820ID Datasheet(HTML) 13 Page - Texas Instruments |
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13 / 32 page ![]() OPA820 SBOS303C − JUNE 2004 − REVISED AUGUST 2008 www.ti.com 13 APPLICATIONS INFORMATION WIDEBAND VOLTAGE-FEEDBACK OPERATION The combination of speed and dynamic range offered by the OPA820 is easily achieved in a wide variety of application circuits, providing that simple principles of good design practice are observed. For example, good power-supply decoupling, as shown in Figure 1, is essential to achieve the lowest possible harmonic distortion and smooth frequency response. Proper PC board layout and careful component selection will maximize the performance of the OPA820 in all applications, as discussed in the following sections of this data sheet. Figure 1 shows the gain of +2 configuration used as the basis for most of the typical characteristics. Most of the curves were characterized using signal sources with 50 Ω driving impedance and with measurement equipment presenting 50 Ω load impedance. In Figure 1, the 50Ω shunt resistor at the VI terminal matches the source impedance of the test generator while the 50 Ω series resistor at the VO terminal provides a matching resistor for the measurement equipment load. Generally, data sheet specifications refer to the voltage swings at the output pin (VO in Figure 1). The 100Ω load, combined with the 804 Ω total feedback network load, presents the OPA820 with an effective load of approximately 90 Ω in Figure 1. OPA820 +5V −5V −V S +V S R S 50 Ω V O V IN 50 Ω 2.2 µF 2.2 µF 0.1 µF R G 402 Ω R F 402 Ω 50 Ω Source 50 Ω Load 0.1 µF Figure 1. Gain of +2, High-Frequency Application and Characterization Circuit WIDEBAND INVERTING OPERATION Operating the OPA820 as an inverting amplifier has several benefits and is particularly useful when a matched 50 Ω source and input impedance is required. Figure 2 shows the inverting gain of −1 circuit used as the basis of the inverting mode typical characteristics. OPA820 +5V −5V 50 Ω V O V I 0.1 µF 2.2 µF 0.1 µF 2.2 µF R M 57.6 Ω R T 205 Ω R F 402 Ω 50 Ω Source 50 Ω Load 0.01 µF R G 402 Ω Figure 2. Inverting G = −1 Specifications and Test Circuit In the inverting case, just the feedback resistor appears as part of the total output load in parallel with the actual load. For the 100 Ω load used in the typical characteristics, this gives a total load of 80 Ω in this inverting configuration. The gain resistor is set to get the desired gain (in this case 402 Ω for a gain of −1) while an additional input matching resistor (RM) can be used to set the total input impedance equal to the source if desired. In this case, RM = 57.6Ω in parallel with the 402Ω gain setting resistor gives a matched input impedance of 50 Ω. This matching is only needed when the input needs to be matched to a source impedance, as in the characterization testing done using the circuit of Figure 2. The OPA820 offers extremely good DC accuracy as well as low noise and distortion. To take full advantage of that DC precision, the total DC impedance looking out of each of the input nodes must be matched to get bias current cancellation. For the circuit of Figure 2, this requires the 205 Ω resistor shown to ground on the noninverting input. The calculation for this resistor includes a DC-coupled 50 Ω source impedance along with RG and RM. Although this resistor will provide cancellation for the bias current, it must be well decoupled (0.01 µF in Figure 2) to filter the noise contribution of the resistor and the input current noise. As the required RG resistor approaches 50Ω at higher gains, the bandwidth for the circuit in Figure 2 will far exceed the bandwidth at that same gain magnitude for the noninverting circuit of Figure 1. This occurs due to the lower noise gain for the circuit of Figure 2 when the 50 Ω source impedance is included in the analysis. For instance, at a signal gain of −10 (RG = 50Ω, RM = open, RF = 499Ω) the noise gain for the circuit of Figure 2 will be 1 + 499 Ω/(50Ω + 50Ω) = 6 as a result of adding the 50 Ω source in the noise gain equation. This gives considerable higher bandwidth than the noninverting gain of +10. Using the 240MHz gain bandwidth product for the OPA820, an inverting gain of −10 from a 50 Ω source to a 50Ω RG gives 55MHz bandwidth, whereas the noninverting gain of +10 gives 30MHz. |
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