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TPA2000D4DAP Datasheet(PDF) 16 Page - Texas Instruments

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Part # TPA2000D4DAP
Description  STEREO 2-W CLASS-D AUDIO POWER AMPLIFIER WITH STEREO HP AMPLIFIER
PDF  24 Pages
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Manufacturer  TI [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI - Texas Instruments

TPA2000D4DAP Datasheet(HTML) 16 Page - Texas Instruments

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TPA2000D4
STEREO 2-W CLASS-D AUDIO POWER AMPLIFIER
WITH STEREO HP AMPLIFIER
SLOS337A – DECEMBER 2000 – REVISED MAY 2003
16
POST OFFICE BOX 655303
• DALLAS, TEXAS 75265
APPLICATION INFORMATION
0 V
–5 V
5 V
Current
OUT+
OUT–
Differential
Voltage
Across
Load
0 V
–5 V
5 V
Current
OUT+
OUT–
Differential
Voltage
Across
Load
Output = 0 V
Output > 0 V
Figure 28. The TPA2000D4 Output Voltage and Current Waveforms Into an Inductive Load
efficiency: why you must use a filter with the traditional class-D modulation scheme
The main reason that the traditional class-D amplifier needs an output filter is that the switching waveform
results in maximum current flow. This causes more loss in the load, which causes lower efficiency. The ripple
current is large for the traditional modulation scheme because the ripple current is proportional to voltage
multiplied by the time at that voltage. The differential voltage swing is 2
× VDD and the time at each voltage is
half the period for the traditional modulation scheme. An ideal LC filter is needed to store the ripple current from
each half cycle for the next half cycle, while any resistance causes power dissipation. The speaker is both
resistive and reactive, whereas an LC filter is almost purely reactive.
The TPA2000D4 modulation scheme has very little loss in the load without a filter because the pulses are very
short and the change in voltage is VDD instead of 2 × VDD. As the output power increases, the pulses widen,
making the ripple current larger. Ripple current could be filtered with an LC filter for increased efficiency, but for
most applications the filter is not needed.
An LC filter with a cutoff frequency less than the class-D switching frequency allows the switching current to flow
through the filter instead of the load. The filter has less resistance than the speaker that results in less power
dissipated, which increases efficiency.



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