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SC2616 Datasheet(PDF) 13 Page - Semtech Corporation |
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SC2616 Datasheet(HTML) 13 Page - Semtech Corporation |
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13 / 17 page ![]() 13 2003 Semtech Corp. www.semtech.com POWER MANAGEMENT SC2616 Compensation Components Once the filter components have been determined, the compensation components can be calculated. The goal of compensation is to modify the frequency response characteristics of the error amplifier to ensure that the closed loop feedback system has the highest gain and bandwidth possible while maintaining stability. A simplified stability criteria states that the open loop gain of the converter should fall through 0dB at 20dB/ decade at a frequency no higher than 20-25% of the switching frequency. This objective is most simply met by generating asymp- totic bode plots of the small signal response of the vari- ous sections of the converter. It is convenient to split the converter into two sections, the Error amp and compensation components being one section and the Modulator, output filter and divider be- ing the other. First calculate the DC Filter + Modulator + Divider gain. The DC filter gain is always 0dB, the Modulator gain is 19dB at 5V in and is proportional to Vin, so modulator gain at any input voltage is. ⋅ + = 5 V Log 20 19 G IN MOD the divider gain is given by + ⋅ = B A B DIV R R R Log G 20 So the total Filter + Modulator + Divider DC Gain is + ⋅ + ⋅ + = B A B IN FMD R R R Log V Log G 20 5 20 19 L VOUT Co SC2610 AND FETS FB OUT COMP Ra MODULATOR REF + - EA Rb Resr Zp Zf Zs Applications Information (Cont.) Calculate the filter double pole frequency (Fp(lc)) LCo ) lc ( Fp π = 2 1 and calculate ESR Zero frequency (Fz(esr)) sr Re Co ) esr ( Fz ⋅ ⋅ π = 2 1 Choose an open loop crossover frequency (Fco) no higher than 20% of the switching frequency (Fs). The proximity of Fz(esr) to the crossover frequency Fco determines the type of compensation required, if Fz(esr)>Fco/4, use type 3 compensation, otherwise use type 2. Type 1 compensation is not appropriate and is not discussed here. Type 2 Example As an example of type 2 compensation, we will use the Evaluation board schematic. The total Filter+Modulator+Divider DC Gain is: dB 6 . 13 06 . 8 98 . 6 06 . 8 Log 20 5 5 Log 20 19 G FMD = + ⋅ + ⋅ + = This is drawn as the line A-B in Figure 5. kHz . . LCo ) lc ( Fp 6 1 10 3000 10 3 3 2 1 2 1 6 6 ≈ ⋅ ⋅ ⋅ π = π = − − 3.3uH VOUT 3000uF SC2616 AND FETS FB OUT COMP 6.98k MODULATOR REF + - EA 8.06k 22mOhm Cs Cp Rs Vin=5V |
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