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IR3086AM Datasheet(PDF) 28 Page - International Rectifier |
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IR3086AM Datasheet(HTML) 28 Page - International Rectifier |
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28 / 33 page ![]() IR3086A RPHASE41=10kΩ, RPHASE42=768Ω, RPHASE43=2.80kΩ Bootstrap Capacitor CBST Choose CBST=0.1uF Decoupling Capacitors for Phase IC and Power Stage Choose CVCC=0.1uF, CVCCL=0.1uF VOLTAGE LOOP COMPENSATION Type III compensation is used for the converter with only ceramic output capacitors. The crossover frequency and phase margin of the voltage loop can be estimated as follows. kHz R R G C R f LE FB CS E DRP C 146 ) 6 / 10 * 5 . 0 ( 162 34 ) 10 * 22 62 ( 2 576 2 3 6 1 = ∗ ∗ ∗ ∗ ∗ = ∗ ∗ ∗ ∗ = − − π π ° = ∗ − = 63 180 ) 5 . 0 tan( 90 1 π θ A C Choose Ω = ∗ = ∗ = 110 162 3 2 3 2 1 FB FB R R Choose the desired crossover frequency fc (=140kHz) around fc1 estimated above, and calculate nF R f C FB C FB 2 . 5 110 10 * 140 4 1 4 1 3 1 = ∗ ∗ = ∗ ∗ = π π , choose CFB=5.6nF nF R C R R C DRP FB FB FB DRP 7 . 2 576 10 * 6 . 5 ) 110 162 ( ) ( 9 1 = ∗ + = ∗ + = − Ω = − ∗ ∗ ∗ ∗ ∗ = ∗ ∗ ∗ ∗ ∗ = − − − k V V R C L f R O RAMP FB E E C CP 65 . 1 10 * 20 3 . 1 75 . 0 * 162 ) 62 10 * 22 ( ) 6 / 10 * 100 ( ) 10 * 140 2 ( ) 2 ( 3 6 9 2 3 2 π π nF R C L C CP E E CP 27 10 65 . 1 ) 62 * 10 * 22 ( ) 6 / 10 * 100 ( 10 10 3 6 9 = ∗ ∗ ∗ = ∗ ∗ = − − Choose CCP1=47pF to reduce high frequency noise. CURRENT SHARE LOOP COMPENSATION The crossover frequency of the current share loop fCI should be at least one decade lower than that of the voltage loop fC. Choose the crossover frequency of current share loop fCI=3.5kHz, and calculate CSCOMP, 011 . 0 ) 3 . 1 12 ( * ) 3 . 1 75 . 0 12 ( 75 . 0 * 10 * 800 * 10 * 100 * 10 * 2 . 18 ) ( * ) ( * * * 3 12 3 = − − − = − − − = − DAC I DAC PWMRMP I PWMRMP SW PWMRMP PWMRMP MI V V V V V V f C R F 6 _ 10 * 05 . 1 * 2 * )] ( * * * 2 1 [ * * * * * * 65 . 0 CI O MI O O E CI LE ROOM CS O I PWMRMP SCOMP f V F I V C f R G I V R C ∗ ∗ + = π π 6 4 4 6 3 3 10 * 05 . 1 * 3500 2 ) 10 * 1 . 9 * 105 33 . 1 ( 011 . 0 * ] 105 ) 10 * 1 . 9 * 105 33 . 1 ( * 62 * 10 * 22 * 3500 * 2 1 [ * ) 6 10 * 5 . 0 ( * 34 * 105 * 12 * 10 * 2 . 18 * 65 . 0 ∗ ∗ − − + = − − − − π π nF 6 . 20 = Choose CSCOMP=22nF Page 28 of 33 1/31/05 |
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