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SN6501DBVT Datasheet(PDF) 14 Page - Texas Instruments |
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SN6501DBVT Datasheet(HTML) 14 Page - Texas Instruments |
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14 / 26 page ![]() max IN-max min IN-max min T V Vt V = 2 2 f ³ ´ ´ . min min 3.6 V Vt = 7.2 Vμs for 3.3 V, and 2 250 kHz 5.5 V Vt = 9.1 Vμs for 5 V applications 2 300 kHz ³ ´ ³ ´ Q VIN VF RL RDS VDS VDO VP VI VO VS SN6501 SLLSEA0C – FEBRUARY 2012 – REVISED MARCH 2012 www.ti.com TRANSORMER SELECTION V-t Product Calculation To prevent a transformer from saturation its V-t product must be greater than the maximum V-t product applied by the SN6501. The maximum voltage delivered by the SN6501 is the nominal converter input plus 10%. The maximum time this voltage is applied to the primary is half the period of the lowest frequency at the specified input voltage. Therefore, the transformer’s minimum V-t product is determined through: (1) Inserting the numeric values from the data sheet into the equation above yields the minimum V-t products of (2) Common V-t values for low-power center-tapped transformers range from 22 V μs to 150 Vμs with typical footprints of 10 mm x 12 mm. However, transformers specifically designed for PCMCIA applications provide as little as 11 V μs and come with a significantly reduced footprint of 6 mm x 6 mm only. While Vt-wise all of these transformers can be driven by the SN6501, other important factors such as isolation voltage, transformer wattage, and turns ratio must be considered before making the final decision. Turns Ratio Estimate Assume the rectifier diodes and linear regulator has been selected. Also, it has been determined that the transformer choosen must have a V-t product of at least 11 V μs. However, before searching the manufacturer websites for a suitable transformer, the user still needs to know its minimum turns ratio that allows the push-pull converter to operate flawlessly over the specified current and temperature range. This minimum transformation ratio is expressed through the ratio of minimum secondary to minimum primary voltage multiplied by a correction factor that takes the transformer’s typical efficiency of 97% into account: VP-min = VIN-min - VDS-max (3) VS-min must be large enough to allow for a maximum voltage drop, VF-max, across the rectifier diode and still provide sufficient input voltage for the regulator to remain in regulation. From the LDO SELECTION section, this minimum input voltage is known and by adding VF-max gives the minimum secondary voltage with: VS-min = VF-max + VDO-max + VO-max (4) Figure 35. Establishing the Required Minimum Turns Ratio Through nmin = 1.031 × VS-min / VP-min Then calculating the available minimum primary voltage, VP-min, involves subtracting the maximum possible drain- source voltage of the SN6501, VDS-max, from the minimum converter input voltage VIN-min: 14 Submit Documentation Feedback Copyright © 2012, Texas Instruments Incorporated Product Folder Link(s) :SN6501 |
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