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AD623 Datasheet(PDF) 15 Page - Analog Devices |
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AD623 Datasheet(HTML) 15 Page - Analog Devices |
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15 / 16 page ![]() AD623 –15– REV. C Amplifying Signals with Low Common-Mode Voltage Because the common-mode input range of the AD623 extends 0.1 V below ground, it is possible to measure small differential signals which have low, or no, common mode component. Fig- ure 50 shows a thermocouple application where one side of the J-type thermocouple is grounded. J-TYPE THERMOCOUPLE 2V +5V VOUT 0.1 F AD623 REF RG 1.02k Figure 50. Amplifying Bipolar Signals with Low Common- Mode Voltage Over a temperature range from –200 °C to +200°C, the J-type thermocouple delivers a voltage ranging from –7.890 mV to 10.777 mV. A programmed gain on the AD623 of 100 (RG = 1.02 k Ω) and a voltage on the AD623 REF pin of 2 V, results in the AD623’s output voltage ranging from 1.110 V to 3.077 V relative to ground. INPUT DIFFERENTIAL AND COMMON-MODE RANGE VS. SUPPLY AND GAIN Figure 51 shows a simplified block diagram of the AD623. The voltages at the outputs of the amplifiers A1 and A2 are given by the equations VA2 = VCM + VDIFF/2 + 0.6 V + VDIFF × RF/RG = VCM + 0.6 V + VDIFF × Gain/2 VA1 = VCM – VDIFF/2 + 0.6 V – VDIFF × RF/RG = VCM + 0.6 V – VDIFF × Gain/2 50k VOUT 6 REF 5 50k 50k 50k 1 POS SUPPLY 7 INVERTING 2 4 NEG SUPPLY 3 NONINVERTING 7 GAIN VDIFF 2 VCM RF 50k RG A1 4 8 RF 50k A3 A2 VDIFF 2 Figure 51. Simplified Block Diagram The voltages on these internal nodes are critical in determining whether or not the output voltage will be clipped. The voltages VA1 and VA2 can swing from about 10 mV above the negative supply (V– or Ground) to within about 100 mV of the positive rail before clipping occurs. Based on this and from the above equations, the maximum and minimum input common-mode voltages are given by the equations VCMMAX = V+ – 0.7 V – VDIFF × Gain/2 VCMMIN = V– – 0.590 V + VDIFF × Gain/2 These equations can be rearranged to give the maximum possible differential voltage (positive or negative) for a particular common- mode voltage, gain, and power supply. Because the signals on A1 and A2, can clip on either rail, the maximum differential voltage will be the lesser of the two equations. |VDIFFMAX| = 2 (V+ – 0.7 V – VCM)/Gain |VDIFFMAX| = 2 (VCM – V– +0.590 V)/Gain However, the range on the differential input voltage range is also constrained by the output swing. So the range of VDIFF may have to be lower according the equation. Input Range ≤ Available Output Swing/Gain For a bipolar input voltage with a common-mode voltage that is roughly half way between the rails, VDIFFMAX will be half the value that the above equations yield because the REF pin will be at midsupply. Note that the available output swing is given for different supply conditions in the Specifications section. The equations can be rearranged to give the maximum gain for a fixed set of input conditions. Again, the maximum gain will be the lesser of the two equations. GainMAX = 2 (V+ – 0.7 V – VCM)/VDIFF GainMAX = 2 (VCM – V– +0.590 V)/VDIFF Again, we must ensure that the resulting gain times the input range is less than the available output swing. If this is not the case, the maximum gain is given by, GainMAX = Available Output Swing/Input Range Also for bipolar inputs (i.e., input range = 2 VDIFF), the maxi- mum gain will be half the value yielded by the above equations because the REF pin must be at midsupply. The maximum gain and resulting output swing for different input conditions is given in Table IV. Output voltages are refer- enced to the voltage on the REF pin. For the purposes of computation, it is necessary to break down the input voltage into its differential and common-mode compo- nent. So when one of the inputs is grounded or at a fixed voltage, the common-mode voltage changes as the differential voltage changes. Take the case of the thermocouple amplifier in Figure 50. The inverting input on the AD623 is grounded. So when the input voltage is –10 mV, the voltage on the noninverting input is –10 mV. For the purposes of signal swing calculations, this input voltage should be considered to be composed of a common-mode voltage of –5 mV (i.e., (+IN + –IN)/2) and a differential input voltage of –10 mV (i.e., +IN – –IN). |
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