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LM4818 Datasheet(PDF) 11 Page - National Semiconductor (TI) |
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LM4818 Datasheet(HTML) 11 Page - National Semiconductor (TI) |
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11 / 16 page ![]() Application Information (Continued) C B T ON 0.47µF 940ms 1.0µF 2S In order to eliminate ’clicks and pops’, all capacitors must be discharged before turn-on. Rapidly switching V DD may not allow the capacitors to fully discharge, which may cause ’clicks and pops’. AUDIO POWER AMPLIFIER DESIGN EXAMPLE The following are the desired operational parameters: Given: Power Output 100mW Load Impedance 16 Ω Input Level 1Vrms (max) Input Impedance 20k Ω Bandwidth 100Hz–20kHz ± 0.25dB The design begins by specifying the minimum supply voltage necessary to obtain the specified output power. To find this minimum supply voltage, use the Output Power vs. Supply Voltage graph in the Typical Performance Characteristics section. From the graph for a 16 Ω load, (graphs are for 8Ω, 16 Ω, and 32Ω loads) the supply voltage for 100mW of output power with 1% THD+N is approximately 3.15 volts. Additional supply voltage creates the benefit of increased headroom that allows the LM4818 to reproduce peaks in excess of 100mW without output signal clipping or audible distortion. The choice of supply voltage must also not create a situation that violates maximum dissipation as explained above in the Power Dissipation section. For example, if a 3.3V supply is chosen for extra headroom then according to Equation (3) the maximum power dissipation point with a 16 Ω load is 138mW. Using Equation (4) the maximum am- bient temperature is 126˚C for the M08A package. After satisfying the LM4818’s power dissipation require- ments, the minimum differential gain is found using Equation (6). (6) Thus a minimum gain of 1.27 V/V allows the LM4818 to reach full output swing and maintain low noise and THD+N performance. For this example, let A VD = 1.27. The amplifi- er’s overall gain is set using the input (R i) and feedback (RF) resistors. With the desired input impedance set to 20k Ω, the feedback resistor is found using Equation (7). R F/Ri =AVD/2 (V/V) (7) The value of R F is 13kΩ. The last step in this design example is setting the amplifier’s -3dB frequency bandwidth. To achieve the desired ±0.25dB pass band magnitude variation limit, the low frequency re- sponse must extend to at least one-fifth the lower bandwidth limit and the high frequency response must extend to at least five times the upper bandwidth limit. The gain variation for both response limits is 0.17dB, well with in the ±0.25dB desired limit. The results are: f L = 100Hz/5 = 20Hz f H = 20 kHz*5 = 100kHz As mentioned in the External Components section, R i and C i create a high pass filter that sets the amplifier’s lower band pass frequency limit. Find the coupling capacitor’s value using Equation (8). C i ≥ 1/(2πRifc) (F) (8) C i ≥ 0.398µF, a standard value of 0.39µF will be used. The product of the desired high frequency cutoff (100kHz in this example) and the differential gain, A VD, determines the up- per pass band response limit. With A VD = 1.27 and fH = 100kHz, the closed-loop gain bandwidth product (GBWP) is 127kHz. This is less than the LM4818’s 900kHz GBWP. With this margin the amplifier can be used in designs that require more differential gain while avoiding performance restricting bandwidth limitations. www.national.com 11 |
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