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CS48520 Datasheet(PDF) 10 Page - Cirrus Logic |
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CS48520 Datasheet(HTML) 10 Page - Cirrus Logic |
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10 / 23 page ![]() 10 DS734F5 5.4 Power Supply Characteristics 5.4 Power Supply Characteristics (Measurements performed under operating conditions) 5.5 Thermal Data (48-pin LQFP) Parameter Symbol Min Typ Max Unit High-level input voltage VIH 2.0 — — V Low-level input voltage, except XTI VIL —— 0.8 V Low-level input voltage, XTI VILXTI —— 0.6 V Input hysteresis Vhys —0.4 — V High-level output voltage (IO = –2 mA), except XTI VOH VDDIO*0.9 — — V Low-level output voltage (IO = 2 mA), except XTI VOL —— VDDIO*0.1 V Input leakage XTI ILXTI —— 5 µA Input leakage current (all digital pins with internal pull-up resistors enabled) ILEAK —— 70 µA Parameter Min Typ Max Unit Operational Power Supply Current: VDD: Core and I/O operating1 1.Dependent on application firmware and DSP clock speed. — 203 — mA VDDA: PLL operating —8 — mA VDDIO: With most ports operating —27 — mA Total Operational Power Dissipation: — 480 — mW Standby Power Supply Current: VDD: Core and I/O not clocked — 100 — µA VDDA: PLL halted —1 — µA VDDIO: All connected I/O pins 3-stated by other ICs in system — 50 — µA Total Standby Power Dissipation — 348 — µW Parameter Symbol Min Typ Max Unit Junction Temperature Tj —— 125 °C Thermal Resistance (Junction to Ambient) Two-layer board1 Four-layer board2 1.Two-layer board is specified as a 76 mm X 114 mm, 1.6 mm thick FR-4 material with 1 oz. copper covering 20% of the top and bottom layers. 2.Four-layer board is specified as a 76 mm X 114 mm, 1.6 mm thick FR-4 material with 1 oz. copper covering 20% of the top and bottom layers and 0.5 oz. copper covering 90 % of the internal power plane and ground plane layers. θ ja — 63.5 — °C/Watt —54 — Thermal Resistance (Junction to Top of Package) Two-layer board3 Four-layer board4 3.To calculate the die temperature for a given power dissipation T j = Ambient Temperature + [(Power Dissipation in Watts)* θ ja] 4.To calculate the case temperature for a given power dissipation T c = Tj – [(Power Dissipation in Watts)* ψ jt] ψ jt — 0.70 — °C/Watt —0.64 — |
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