Electronic Components Datasheet Search
  English  ▼

X  

AD7910 Datasheet(PDF) 5 Page - Analog Devices

Part # AD7910
Description  250 kSPS, 10-/12-Bit ADCs in 6-Lead SC70
PDF  20 Pages
Scroll/Zoom Zoom In 100%  Zoom Out
Manufacturer  AD [Analog Devices]
Direct Link  http://www.analog.com
Logo AD - Analog Devices

AD7910 Datasheet(HTML) 5 Page - Analog Devices

  AD7910 Datasheet HTML 1Page - Analog Devices AD7910 Datasheet HTML 2Page - Analog Devices AD7910 Datasheet HTML 3Page - Analog Devices AD7910 Datasheet HTML 4Page - Analog Devices AD7910 Datasheet HTML 5Page - Analog Devices AD7910 Datasheet HTML 6Page - Analog Devices AD7910 Datasheet HTML 7Page - Analog Devices AD7910 Datasheet HTML 8Page - Analog Devices AD7910 Datasheet HTML 9Page - Analog Devices Next Button
Zoom Inzoom in Zoom Outzoom out
 5 / 20 page
background image
REV. B
AD7910/AD7920
–5–
CS
SCLK
SDATA
t2
t6
t3
t4
t7
t5
t8
tCONVERT
tQUIET
ZERO
ZERO
ZERO
DB11
DB10
DB2
DB1
DB0
B
THREE-STATE
THREE-
STATE
Z
4 LEADING ZEROS
12
345
13
14
15
16
t1
Figure 2. AD7920 Serial Interface Timing Diagram
CS
SCLK
t2
tCONVERT
B
1
234
5
13
14
15
16
C
t8
tQUIET
tACQ
12.5(1/fSCLK)
1/THROUGHPUT
Figure 3. Serial Interface Timing Example
TO OUTPUT
PIN
CL
50pF
200 A
IOH
200 A
IOL
1.6V
Figure 1. Load Circuit for Digital Output Timing
Specifications
TIMING EXAMPLES
Figures 2 and 3 show some of the timing parameters from the
Timing Specifications table.
Timing Example 1
From Figure 3, having fSCLK = 5 MHz and a throughput rate of
250 kSPS gives a cycle time of t2 + 12.5(1/fSCLK) + tACQ = 4
ms.
With t2 = 10 ns min, this leaves tACQ to be 1.49
ms. This 1.49 ms
satisfies the requirement of 250 ns for tACQ. From Figure 3, tACQ
comprises 2.5(1/fSCLK) + t8 + tQUIET, where t8 = 36 ns max. This
allows a value of 954 ns for tQUIET, satisfying the minimum re-
quirement of 50 ns.
Timing Example 2
The AD7920 can also operate with slower clock frequencies.
From Figure 3, having fSCLK = 3.4 MHz and a throughput rate
of 150 kSPS gives a cycle time of t2 + 12.5(1/fSCLK) + tACQ =
6.66
ms. With t2 = 10 ns min, this leaves tACQ to be 2.97 ms. This
2.97
ms satisfies the requirement of 250 ns for tACQ. From
Figure 3, tACQ comprises 2.5(1/fSCLK) + t8 + tQUIET, t8 = 36 ns
max. This allows a value of 2.19
ms for tQUIET, satisfying the
minimum requirement of 50 ns. As in this example and with
other slower clock values, the signal may already be acquired
before the conversion is complete, but it is still necessary to leave
50 ns minimum tQUIET between conversions. In this example, the
signal should be fully acquired at approximately point C in
Figure 3.



Html Pages

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20


Datasheet Download

Go To PDF Page


Link URL



Does ALLDATASHEET help your business so far?  [ DONATE ] 

About Alldatasheet   |   Advertisement   |   Contact us   |   Privacy Policy   |   Link to Datasheet    |   Link Exchange   |   Manufacturer List
All Rights Reserved©Alldatasheet.com


Mirror Sites
English : Alldatasheet.com  |   English : Alldatasheet.net  |   Chinese : Alldatasheetcn.com  |   German : Alldatasheetde.com  |   Japanese : Alldatasheet.jp
Russian : Alldatasheetru.com  |   Korean : Alldatasheet.co.kr  |   Spanish : Alldatasheet.es  |   French : Alldatasheet.fr  |   Italian : Alldatasheetit.com
Portuguese : Alldatasheetpt.com  |   Polish : Alldatasheet.pl  |   Vietnamese : Alldatasheet.vn
Indian : Alldatasheet.in  |   Mexican : Alldatasheet.com.mx  |   British : Alldatasheet.co.uk  |   New Zealand : Alldatasheet.co.nz
Family Site : ic2ic.com  |   icmetro.com