AP6501

Document number: DS36059 Rev. 1 - 2

11 of 15

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September 2012

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AP6501

Applications Information (cont.)

Inductor (cont.)

Peak current determines the required saturation current rating, which influences the size of the inductor. Saturating the inductor decreases

the converter efficiency while increasing the temperatures of the inductor and the internal MOSFETs. Hence choosing an inductor with

appropriate saturation current rating is important.

A 1µH to 10µH inductor with a DC current rating of at least 25% percent higher than the maximum load current is recommended for most

applications.

For highest efficiency, the inductor’s DC resistance should be less than 200m

Ω. Use a larger inductance for improved efficiency under light

load conditions.

Input Capacitor

The input capacitor reduces the surge current drawn from the input supply and the switching noise from the device. The input capacitor has

to sustain the ripple current produced during the on time on the upper MOSFET. It must hence have a low ESR to minimize the losses.

The RMS current rating of the input capacitor is a critical parameter that must be higher than the RMS input current. As a rule of thumb,

select an input capacitor which has RMs rating that is greater than half of the maximum load current.

Due to large dI/dt through the input capacitors, electrolytic or ceramics should be used. If a tantalum must be used, it must be surge

protected. Otherwise, capacitor failure could occur. For most applications, a 4.7µF ceramic capacitor is sufficient.

Output Capacitor

The output capacitor keeps the output voltage ripple small, ensures feedback loop stability and reduces the overshoot of the output voltage.

The output capacitor is a basic component for the fast response of the power supply. In fact, during load transient, for the first few

microseconds it supplies the current to the load. The converter recognizes the load transient and sets the duty cycle to maximum, but the

current slope is limited by the inductor value.

Maximum capacitance required can be calculated from the following equation:

ESR of the output capacitor dominates the output voltage ripple. The amount of ripple can be calculated from the equation below:

ESR

*

inductor

ΔI

capacitor

Vout

=

An output capacitor with ample capacitance and low ESR is the best option. For most applications, a 22µF ceramic capacitor will be

sufficient.

2

out

2

out

2

inductor

out

o

V

)

V

V

(

Δ

)

2

ΔI

L(I

C

−

+

+

=

Where

ΔV is the maximum output voltage overshoot.