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CS5305 Datasheet(PDF) 22 Page - ON Semiconductor

Part # CS5305
Description  Three?뭁hase Synchronous Switching Step?묭own Controller with Single Wire Current Sharing
PDF  33 Pages
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Manufacturer  ONSEMI [ON Semiconductor]
Direct Link  http://www.onsemi.com
Logo ONSEMI - ON Semiconductor

CS5305 Datasheet(HTML) 22 Page - ON Semiconductor

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CS5305
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22
Share Bus Components
Five external components are required to implement the
module−to−module current
share
function.
These
components set the current sense load line, provide the share
bus pull−down and compensate the share adjust amplifier.
The share current sense amplifier monitors the total
module current and provides a DC voltage output
proportional to that current. The share sense amplifier gain
is programmable and allows the user to set the share bus
transconductance. It is important that all modules in a
system have a share current load line that approximates that
of
all the other modules to ensure accurate
module−to−module current sharing. Let us arbitrarily set the
share bus maximum voltage for full load at 2 V. If a module
is designed to provide 81 A at full load, the module share
transconductance should be 81 A/2 V or 40.5 A/V. Two
resistors and a capacitor set the share current sense amplifier
gain. The resistors set the DC gain while the capacitor
provides a zero to minimize errors due to noise.
The total module current is measured as described in the
section dealing with the OCSET current limit function. That
is, each phase within a module generates a voltage between
the CSx and CSREF leads that is proportional to the current
flow in the output inductor and the inductor’s ESR:
VCSx * VCSREF + (IL)(ESRL)
This signal is amplified by a factor of 3.7 for each phase
and then summed for all three phases. This signal is provided
as input to the share current sense amplifier. If we assume
that all three phases are sharing current equally within a
single module, the input to the share current sense amplifier
can be expressed as:
VIN(SENSE) + 11.1(VCSx * VCSREF)
+ 11.1(IL)(ESRL) + 3.7(IOUT)(ESRL)
If we set IL equal to the maximum per phase current at full
load, and if we know the value of ESR for our inductors, we
can calculate the required share current sense amplifier
gain as:
AV(SHARESENSE) +
share maximimum voltage
VIN(SENSE)
As an example, let us again consider the case for a module
providing full load current of 81 A. Each output phase is
conducting 27 A. If we assume ESR = 1.5 mΩ then input to
the share current sense amplifier is (11.1)(27 A)(1.5 mΩ) =
0.45 V. The required share current sense amplifier gain is
then 2 V/0.45 V = 4.44.
+
RIOUT
CIOUT
IFB
RIFB
VIN(SENSE)
IOUT
Figure 38.
From the schematic in Figure 38, we derive the DC gain as:
AV(SHARESENSE) + 4.44 + RIOUT RIFB ) 1
This specifies that RIOUT should be 3.44 times greater than
RIFB.
Another important consideration is the type of resistor
selected for RIFB. The thermal performance of RIFB must
match that of whatever sense element is being used to monitor
module current. Inductive sensing has been shown to be
reasonably accurate, but copper’s thermal coefficient of
resistivity is approximately +4000 parts per million per °C
(0.4% per °C). In order to maintain accurate control of the
share bus over temperature, RIFB must have a similar thermal
coefficient. This requires a positive temperature coefficient
element such as the KOA−Speer LT73. If a standard sense
resistor is used in series between the inductor and the load,
there is no need to use special resistors for sensing, but
efficiency will suffer due to power dissipation in the sense
resistor.
As regards the value of CIOUT, it should be noted that the
complete transfer function for the share current sense
amplifier in Figure 38 is:
AV(SHARESENSE) +
RIOUT
RIFB(1 ) sCIOUT RIOUT)
) 1
CIOUT causes the gain for high frequency noise to
decrease, thus quieting the share bus.
The share resistor provides a passive pull−down on the
SHARE lead. This allows the share bus voltage to be pulled
all the way down to ground. The share resistor is selected to
satisfy a number of criteria. First, the resistor cannot be made
too small. The SHARE lead source current is guaranteed to
be above 1 mA and must be capable of driving the SHARE
lead voltage to 3 V. The share bus of one module serves as
master to all and drives the total resistance of all SHARE
leads. Thus, the total impedance of all share resistors should
be made greater than or equal to 3 kΩ. That is,



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