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OPA699MJD Datasheet(PDF) 20 Page - Texas Instruments |
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OPA699MJD Datasheet(HTML) 20 Page - Texas Instruments |
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20 / 34 page ![]() www.ti.com R F 402 Ω C S 13pF OPA699 +5V -5V V O V I C F 2.8pF 200 Ω R G 402 Ω V H V L S0052-01 Z O + GBP NG2 1 1 * N G1 N G2 * 1 * 2 N G1 N G2 (1) C F + 1 2pR F Z O N G2 (+ 3 pF) (2) C S + N G2 * 1 C F (3) f *3dB 5 Z O * GBP (4) OPA699M SGLS289A – MAY 2005 – REVISED MARCH 2006 APPLICATION INFORMATION (continued) Figure 51. Broadband, Low-Inverting Gain External Compensation To choose the values for both CS and CF, two parameters and only three equations need to be solved. The first parameter is the target high-frequency noise gain (NG2), which should be greater than the minimum stable gain for the OPA699. Here, a target of NG2 = 26 is used. The second parameter is the desired low-frequency signal gain, which also sets the low-frequency noise gain (NG1). To simplify this discussion, we target a maximally flat 2nd-order low-pass Butterworth frequency response (Q = 0.707). The signal gain shown in Figure 51 sets the low-frequency noise gain to NG1 = 1 + RF/RG (= 2 in this example). Then, using only these two gains and the gain bandwidth product for the OPA699 (1000 MHz), the key frequency in the compensation is set by Equation 1. Physically, this ZO (22.3 MHz for the values shown above) is set by 1/[2πRF(CF + CS)] and is the frequency at which the rising portion of the noise gain would intersect the unity gain if projected back to a 0 dB gain. The actual zero in the noise gain occurs at NG1 × ZO and the pole in the noise gain occurs at NG2 × ZO. That pole is physically set by 1/(RFCF). Since GBP is expressed in Hz, multiply ZO by 2π and use to get CF by solving Equation 2. Finally, since CS and CF set the high-frequency noise gain, determine CS using Equation 3 (solving for CS by using NG2 = 6): which gives CS = 15 pF. Both of these calculated values have been reduced slightly in Figure 51 to account for parasitics. The resulting closed-loop bandwidth is approximately equal to Equation 4. For the values shown in Figure 51, f–3 dB is approximately 149 MHz. This is less than that predicted by simply dividing the GBP product by NG1. The compensation network controls the bandwidth to a lower value, while providing the full slew rate at the output and an improved distortion performance due to increased loop gain at frequencies below NG1 × ZO. 20 Submit Documentation Feedback |
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