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OPA690 Datasheet(PDF) 23 Page - Texas Instruments |
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OPA690 Datasheet(HTML) 23 Page - Texas Instruments |
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23 / 35 page ![]() www.ti.com DRIVING CAPACITIVE LOADS 1/2 OPA2890 50W R F 750W R G 375W R B 261W R M 57.6W Source +5V -5V R O 50W 0.1 F m 6.8 F m + 0.1 F m 0.1 F m 6.8 F m + 50 Load W V O V I = 2V/V - V O V I DISTORTION PERFORMANCE OPA2890 SBOS364A – DECEMBER 2007 – REVISED DECEMBER 2007 discussed in the previous section. The amplifier Combining this resistance in parallel with the output, however, now sees the 100 Ω feedback feedback resistor gives the RB = 261Ω used in this resistor in parallel with the external load. In general, example. To reduce the additional high-frequency the feedback resistor should be limited to the 200 Ω to noise introduced by this resistor, it is sometimes 1.5k Ω range. In this case, it is preferable to increase bypassed with a capacitor. As long as RB < 350Ω, the both the RF and RG values (see Figure 56), and then capacitor is not required because the total noise achieve the input matching impedance with a third contribution of all other terms is less than that of the resistor (RM) to ground. The total input impedance op amp input noise voltage. As a minimum, the becomes the parallel combination of RG and RM. OPA2890 requires an RB value of 50Ω to damp out parasitic-induced peaking—a direct short to ground on the noninverting input runs the risk of a very high-frequency instability in the input stage. One of the most demanding and yet very common load conditions for an op amp is capacitive loading. Often, the capacitive load is the input of an ADC—including additional external capacitance that may be recommended to improve ADC linearity. A high-speed, high open-loop gain amplifier such as the OPA2890 can be very susceptible to decreased stability and closed-loop response peaking when a capacitive load is placed directly on the output pin. When the open-loop output resistance of the amplifier is considered, this capacitive load introduces an additional pole in the signal path that can decrease the phase margin. Several external solutions to this problem have been suggested. When the primary considerations are frequency response flatness, pulse response fidelity, and/or distortion, the simplest and most effective solution is to isolate the capacitive Figure 59. Gain of –2V/V Example Circuit load from the feedback loop by inserting a series-isolation resistor between the amplifier output and the capacitive load. This solution does not The second major consideration, touched on in the eliminate the pole from the loop response, but rather previous paragraph, is that the signal source shifts it and adds a zero at a higher frequency. The impedance becomes part of the noise gain equation additional zero acts to cancel the phase lag from the and influences the bandwidth. For the example in capacitive load pole, thus increasing the phase Figure 59, the RM value combined in parallel with the margin and improving stability. external 50 Ω source impedance yields an effective driving impedance of 50 Ω || 57.6Ω = 26.7Ω. This The Typical Characteristics show the recommended impedance is added in series with RG for calculating RS versus capacitive load (see Figure 15 and the noise gain (NG). The resultant NG is 2.86V/V for Figure 36) and the resulting frequency response at Figure 59, as opposed to only 2V/V if RM could be the load. Parasitic capacitive loads greater than 2pF eliminated as discussed above. Therefore, the can begin to degrade the performance of the bandwidth is slightly lower for the gain of –2V/V OPA2890. Long PCB traces, unmatched cables, and circuit of Figure 59 than for the gain of +2V/V circuit connections to multiple devices can easily exceed of Figure 49. this value. Always consider this effect carefully, and add the recommended series resistor as close as The third important consideration in inverting amplifier possible to the OPA2890 output pin (see the Board design is setting the bias current cancellation resistor Layout Guidelines section). on the noninverting input (RB). If this resistor is set equal to the total dc resistance looking out of the inverting node, the output dc error (as a result of the input bias currents) is reduced to [(Input Offset The OPA2890 provides good distortion performance Current) × R F]. If the 50 Ω source impedance is into a 100 Ω load on ±5V supplies. Relative to DC-coupled in Figure 57, the total resistance to alternative solutions, it provides exceptional ground on the inverting input is 402 Ω. performance into lighter loads and/or operating on a single +5V supply. Generally, until the fundamental Copyright © 2007, Texas Instruments Incorporated Submit Documentation Feedback 23 Product Folder Link(s): OPA2890 |
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