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THS4521 Datasheet(PDF) 32 Page - Texas Instruments |
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THS4521 Datasheet(HTML) 32 Page - Texas Instruments |
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32 / 58 page ![]() −21 −18 −15 −12 −9 −6 −3 0 3 6 9 100k 1M 10M 100M Frequency (Hz) RF = 2 k Ω RF = 10 k Ω RF = 100 k Ω VOUT = 100 mVPP G067 32 THS4531 SLOS358C – SEPTEMBER 2011 – REVISED APRIL 2020 www.ti.com Product Folder Links: THS4531 Submit Documentation Feedback Copyright © 2011–2020, Texas Instruments Incorporated Application Circuits (continued) 9.2.7 Low Power Applications and the Effects of Resistor Values on Bandwidth The THS4531 is designed for the nominal value of RF to be 2 kΩ. This gives excellent distortion performance, maximum bandwidth, best flatness, and best pulse response. It also loads the amplifier. For example, in gain of 1 with RF = RG = 2 kΩ, RG to ground, and VOUT+ = 4 V, 1 mA of current will flow through the feedback path to ground. In low power applications, it is desirable to reduce this current by increasing the gain setting resistors values. Using larger value gain resistors has two primary side effects (other than lower power) due to their interaction with the device and PCB parasitic capacitance: 1. Lowers the bandwidth. 2. Lowers the phase margin a. This will cause peaking in the frequency response. b. And will cause over shoot and ringing in the pulse response. Figure 77 shows the small signal frequency response for gain of 1 with RF and RG equal to 2 kΩ, 10 kΩ, and 100 kΩ. The test was done with RL = 2 kΩ. Due to loading effects of RL, lower values may reduce the peaking, but higher values will not have a significant effect. As expected, larger value gain resistors cause lower bandwidth and peaking in the response (peaking in frequency response is synonymous with overshoot and ringing in pulse response). Figure 77. THS4531 Frequency Response with Various Gain Setting Resistor Values 9.2.8 Driving Capacitive Loads The THS4531 is designed for a nominal capacitive load of 2 pF (differentially). When driving capacitive loads greater than this, it is recommended to use small resisters (RO) in series with the output as close to the device as possible. Without RO, capacitance on the output will interact with the output impedance of the amplifier causing phase shift in the loop gain of the amplifier that will reduce the phase margin resulting in: 1. Peaking in the frequency response. 2. Overshoot, undershoot, and ringing in the time domain response with a pulse or square-wave signal. 3. May lead to instability or oscillation. Inserting RO will compensate the phase shift and restore the phase margin, but it will also limit bandwidth. The circuit shown in Figure 69 is used to test for best RO versus capacitive loads, CL, with a capacitance placed differential across the VOUT+ and VOUT- along with 2 kΩ load resistor, and the output is measure with a differential probe. Figure 78 shows the optimum values of RO versus capacitive loads, CL, and Figure 79 shows the frequency response with various values. Performance is the same on both 2.7 V and 5 V supply. |
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