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LM4766 Datasheet(PDF) 17 Page - National Semiconductor (TI)

[Old version datasheet] Texas Instruments acquired National semiconductor. Click here to check the latest version.
Part # LM4766
Description  Audio Power Amplifier Series Dual 40W Audio Power Amplifier with Mute
PDF  19 Pages
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Manufacturer  NSC [National Semiconductor (TI)]
Direct Link  http://www.national.com
Logo NSC - National Semiconductor (TI)

LM4766 Datasheet(HTML) 17 Page - National Semiconductor (TI)

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Application Information (Continued)
AUDIO POWER AMPLlFIER DESIGN
Design a 30W/8
Ω Audio Amplifier
Given:
Power Output
30Wrms
Load Impedance
8
Ω
Input Level
1Vrms(max)
Input Impedance
47k
Ω
Bandwidth
20Hz−20kHz
±0.25dB
A designer must first determine the power supply require-
ments in terms of both voltage and current needed to obtain
the specified output power. V
OPEAK can be determined from
Equation (4) and I
OPEAK from Equation (5).
(4)
(5)
To determine the maximum supply voltage the following
conditions must be considered. Add the dropout voltage to
the peak output swing V
OPEAK, to get the supply rail at a
current of I
OPEAK. The regulation of the supply determines
the unloaded voltage which is usually about 15% higher. The
supply voltage will also rise 10% during high line conditions.
Therefore the maximum supply voltage is obtained from the
following equation.
Max supplies
≈ ± (V
OPEAK +VOD) (1 + regulation) (1.1)
For 30W of output power into an 8
Ω load, the required
V
OPEAK is 21.91V. A minimum supply rail of 25.4V results
from adding V
OPEAK and VOD. With regulation, the maximum
supplies are ±32V and the required I
OPEAK is 2.74A from
Equation (5). It should be noted that for a dual 30W amplifier
into an 8
Ω load the I
OPEAK drawn from the supplies is twice
2.74A
PK or 5.48APK. At this point it is a good idea to check
the Power Output vs Supply Voltage to ensure that the
required output power is obtainable from the device while
maintaining low THD+N. In addition, the designer should
verify that with the required power supply voltage and load
impedance, that the required heatsink value
θ
SA is feasible
given system cost and size constraints. Once the heatsink
issues have been addressed, the required gain can be de-
termined from Equation (6).
(6)
From Equation (6), the minimum A
V is:
A
V
≥ 15.5.
By selecting a gain of 21, and with a feedback resistor, R
f =
20k
Ω, the value of R
i follows from Equation (7).
R
i =Rf (AV − 1)
(7)
Thus with R
i =1k
Ω a non-inverting gain of 21 will result.
Since the desired input impedance was 47k
Ω, a value of
47k
Ω was selected for R
IN. The final design step is to
address the bandwidth requirements which must be stated
as a pair of −3dB frequency points. Five times away from a
−3dB point is 0.17dB down from passband response which
is better than the required ±0.25dB specified. This fact re-
sults in a low and high frequency pole of 4Hz and 100kHz
respectively. As stated in the External Components sec-
tion, R
i in conjunction with Ci create a high-pass filter.
C
i
≥ 1/(2π *1kΩ * 4Hz) = 39.8µF;
use 39µF.
The high frequency pole is determined by the product of the
desired high frequency pole, f
H, and the gain, AV. With a
A
V = 21 and fH = 100kHz, the resulting GBWP is 2.1MHz,
which is less than the guaranteed minimum GBWP of the
LM4766 of 8MHz. This will ensure that the high frequency
response of the amplifier will be no worse than 0.17dB down
at 20kHz which is well within the bandwidth requirements of
the design.
www.national.com
17



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