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AD7492 Datasheet(PDF) 12 Page - Analog Devices

Part # AD7492
Description  1.25 MSPS, 16 mW Internal REF and CLK, 12-Bit Parallel ADC
PDF  16 Pages
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Manufacturer  AD [Analog Devices]
Direct Link  http://www.analog.com
Logo AD - Analog Devices

AD7492 Datasheet(HTML) 12 Page - Analog Devices

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REV. 0
AD7492
–12–
CONVST
BUSY
880ns
1.12 s
2 s
tCONVERT
tQUIESCENT
Figure 12. Mode 1 Power Dissipation
Mode 2 (Full Sleep Mode)
Figure 13 shows the AD7492 conversion sequence in Mode 2,
Full Sleep mode, using a throughput rate of approximately
100 SPS. At 5 V supply the current consumption for the part
when converting is 3 mA, while the full sleep current is 1
µA
max. The power dissipated during this power-down is negligible
and thus not worth considering in the total power figure. During
the wake-up phase, the AD7492 will draw typically 1.8 mA. Over-
all power dissipated is:
(880 ns/10 ms)
× (5 × 3 mA) + (500 µs/10 ms) × (5 × 1.8 mA)
= 451.32
µW
CONVST
BUSY
tWAKEUP
880ns
9.5ms
500 s
tCONVERT
tQUIESCENT
10ms
Figure 13. Full Sleep Power Dissipation
Mode 2 (Partial Sleep Mode)
Figure 14 shows the AD7492 conversion sequence in Mode 2,
Partial Sleep mode, using a throughput rate of 1 kSPS. At 5 V
supply the current consumption for the part when converting is
3 mA, while the partial sleep current is 250
µA max. During the
wake-up phase, the AD7492 will draw typically 1.8 mA. Power
dissipated during wake-up and conversion is :
(880 ns/1 ms)
× (5 × 3 mA) + (20 µs/1 ms) × (5 × 1.8 mA) =
193.2
µW
Power dissipated during power-down is:
(979
µs/1 ms) × (5 × 250 µA) = 1.22 mW
Overall power dissipated is:
193.2
µW + 1.22 mW = 1.41 mW
CONVST
BUSY
tWAKEUP
880ns
979 s
20 s
tCONVERT
tQUIESCENT
1ms
Figure 14. Partial Sleep Power Dissipation
VDRIVE
The VDRIVE pin is used as the voltage supply to the digital output
drivers and the digital input circuitry. It is a separate supply
from AVDD and DVDD. The purpose of using a separate supply
for the digital input/output interface is that the user can vary the
output high voltage, VOH, and the logic input levels, VINH and
VINL, from the VDD supply to the AD7492. For example, if
AVDD and DVDD are using a 5 V supply, the VDRIVE pin can be
powered from a 3 V supply. The ADC has better dynamic per-
formance at 5 V than at 3 V, so operating the part at 5 V, while
still being able to interface to 3 V parts, pushes the AD7492 to
the top bracket of high performance 12-bit A/Ds. Of course, the
ADC can have its VDRIVE and DVDD pins connected together
and be powered from a 3 V or 5 V supply. The trigger levels are
VDRIVE
× 0.7 and VDRIVE × 0.3 for the digital inputs.
The pins that are powered from VDRIVE are DB0–DB11, CS,
RD, CONVST, and BUSY.
PS/
FS PIN
As previously mentioned, the PS/
FS pin is used to control the
type of power-down mode that the AD7492 can enter into if
operated in Mode 2. This pin can be hardwired either high or
low, or even controlled by another device. It is important to
note that toggling the PS/
FS pin while in power-down mode will
not switch the part between partial sleep and full sleep modes.
To switch from one sleep mode to another, the AD7492 will have
to be powered up and the polarity of the PS/
FS pin changed. It
can then be powered down to the required sleep mode.
POWER-UP
It is recommended that the user performs a dummy conversion
after power-up, as the first conversion result could be incorrect.
This also ensures that the parts is in the correct mode of opera-
tion. The recommended power-up sequence is as follows:
1 > GND
4 > Digital Inputs
2 > VDD
5 > VIN
3 > VDRIVE
Power vs. Throughput
The two modes of operation for the AD7492 will produce dif-
ferent power versus throughput performances, Mode 1 and
Mode 2; see Operating Modes section of the data sheet for more
detailed descriptions of these modes. Mode 2 is the Sleep Mode
(Partial/Full) of the part and it achieves the optimum power
performance.
Mode 1
Figure 12 shows the AD7492 conversion sequence in Mode 1
using a throughput rate of 500 kSPS. At 5 V supply the current
consumption for the part when converting is 3 mA and the quies-
cent current is 1.8 mA. The conversion time of 880 ns contributes
6.6 mW to the overall power dissipation in the following way:
(880 ns/2
µs) × (5 × 3 mA) = 6.6 mW
The contribution to the total power dissipated by the remaining
1.12
µs of the cycle is 5.04 mW.
(1.12
µs/2 µs) × (5 × 1.8 mA) = 5.04 mW
Thus the power dissipated during each cycle is:
6.6 mW + 5.04 mW = 11.64 mW



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