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AD7492 Datasheet(PDF) 12 Page - Analog Devices |
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AD7492 Datasheet(HTML) 12 Page - Analog Devices |
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12 / 16 page ![]() REV. 0 AD7492 –12– CONVST BUSY 880ns 1.12 s 2 s tCONVERT tQUIESCENT Figure 12. Mode 1 Power Dissipation Mode 2 (Full Sleep Mode) Figure 13 shows the AD7492 conversion sequence in Mode 2, Full Sleep mode, using a throughput rate of approximately 100 SPS. At 5 V supply the current consumption for the part when converting is 3 mA, while the full sleep current is 1 µA max. The power dissipated during this power-down is negligible and thus not worth considering in the total power figure. During the wake-up phase, the AD7492 will draw typically 1.8 mA. Over- all power dissipated is: (880 ns/10 ms) × (5 × 3 mA) + (500 µs/10 ms) × (5 × 1.8 mA) = 451.32 µW CONVST BUSY tWAKEUP 880ns 9.5ms 500 s tCONVERT tQUIESCENT 10ms Figure 13. Full Sleep Power Dissipation Mode 2 (Partial Sleep Mode) Figure 14 shows the AD7492 conversion sequence in Mode 2, Partial Sleep mode, using a throughput rate of 1 kSPS. At 5 V supply the current consumption for the part when converting is 3 mA, while the partial sleep current is 250 µA max. During the wake-up phase, the AD7492 will draw typically 1.8 mA. Power dissipated during wake-up and conversion is : (880 ns/1 ms) × (5 × 3 mA) + (20 µs/1 ms) × (5 × 1.8 mA) = 193.2 µW Power dissipated during power-down is: (979 µs/1 ms) × (5 × 250 µA) = 1.22 mW Overall power dissipated is: 193.2 µW + 1.22 mW = 1.41 mW CONVST BUSY tWAKEUP 880ns 979 s 20 s tCONVERT tQUIESCENT 1ms Figure 14. Partial Sleep Power Dissipation VDRIVE The VDRIVE pin is used as the voltage supply to the digital output drivers and the digital input circuitry. It is a separate supply from AVDD and DVDD. The purpose of using a separate supply for the digital input/output interface is that the user can vary the output high voltage, VOH, and the logic input levels, VINH and VINL, from the VDD supply to the AD7492. For example, if AVDD and DVDD are using a 5 V supply, the VDRIVE pin can be powered from a 3 V supply. The ADC has better dynamic per- formance at 5 V than at 3 V, so operating the part at 5 V, while still being able to interface to 3 V parts, pushes the AD7492 to the top bracket of high performance 12-bit A/Ds. Of course, the ADC can have its VDRIVE and DVDD pins connected together and be powered from a 3 V or 5 V supply. The trigger levels are VDRIVE × 0.7 and VDRIVE × 0.3 for the digital inputs. The pins that are powered from VDRIVE are DB0–DB11, CS, RD, CONVST, and BUSY. PS/ FS PIN As previously mentioned, the PS/ FS pin is used to control the type of power-down mode that the AD7492 can enter into if operated in Mode 2. This pin can be hardwired either high or low, or even controlled by another device. It is important to note that toggling the PS/ FS pin while in power-down mode will not switch the part between partial sleep and full sleep modes. To switch from one sleep mode to another, the AD7492 will have to be powered up and the polarity of the PS/ FS pin changed. It can then be powered down to the required sleep mode. POWER-UP It is recommended that the user performs a dummy conversion after power-up, as the first conversion result could be incorrect. This also ensures that the parts is in the correct mode of opera- tion. The recommended power-up sequence is as follows: 1 > GND 4 > Digital Inputs 2 > VDD 5 > VIN 3 > VDRIVE Power vs. Throughput The two modes of operation for the AD7492 will produce dif- ferent power versus throughput performances, Mode 1 and Mode 2; see Operating Modes section of the data sheet for more detailed descriptions of these modes. Mode 2 is the Sleep Mode (Partial/Full) of the part and it achieves the optimum power performance. Mode 1 Figure 12 shows the AD7492 conversion sequence in Mode 1 using a throughput rate of 500 kSPS. At 5 V supply the current consumption for the part when converting is 3 mA and the quies- cent current is 1.8 mA. The conversion time of 880 ns contributes 6.6 mW to the overall power dissipation in the following way: (880 ns/2 µs) × (5 × 3 mA) = 6.6 mW The contribution to the total power dissipated by the remaining 1.12 µs of the cycle is 5.04 mW. (1.12 µs/2 µs) × (5 × 1.8 mA) = 5.04 mW Thus the power dissipated during each cycle is: 6.6 mW + 5.04 mW = 11.64 mW |
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