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AP5101 Datasheet(PDF) 9 Page - Diodes Incorporated |
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AP5101 Datasheet(HTML) 9 Page - Diodes Incorporated |
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9 / 15 page ![]() AP5101 1.5A Step-Down Converter with 1.4MHz Switching Frequency AP5101 Document number: DS32258 Rev. 1 - 2 9 of 15 www.diodes.com July 2010 © Diodes Incorporated Applications Information (Continued) Component Selection The output voltage can be adjusted from 0.81V to 15V using an external resistor divider. Table 1 shows a list of resistor selection for common output voltages. Resistor R1 is selected based on a design tradeoff between efficiency and output voltage accuracy. For high values of R1 there is less current consumption in the feedback network. However the trade off is output voltage accuracy due to the bias current in the error amplifier. R2 can be determined by the following equation: ⎟⎟ ⎠ ⎞ ⎜⎜ ⎝ ⎛ − × = 1 0.81 OUT V 2 R 1 R VOUT (V) R1 (kΩ) R2 (kΩ) 1.8 80.6 (1%) 64.9 (1%) 2.5 49.9 (1%) 23.7 (1%) 3.3 49.9 (1%) 16.2 (1%) 5.0 49.9 (1%) 9.53 (1%) Table 1. Resistor Selection for Common Output Voltage Compensation Components The AP5101 has an external COMP pin through which system stability and transient response can be controlled. COMP pin is the output of the internal trans-conductance error amplifier. A series capacitor-resistor combination sets a pole-zero combination to control the characteristics of the control system. The DC gain of the voltage feedback loop is given by: OUT V FB V VEA A CS G LOAD R VDC A × × × = Where VFB is the feedback voltage (0.810V), RLOAD is the load resistor value, GCS is the current sense trans-conductance and AVEA is the error amplifier voltage gain. The control loop transfer function incorporates two poles. One is due to the compensation capacitor (C3) and the output resistor of error amplifier, and the other is due to the output capacitor and the load resistor. These poles are located at: VEA A 3 C 2 EA G P1 f × × π = LOAD R 2 C 2 1 P2 f × × π = Where GEA is the error amplifier trans-conductance. One zero is present due to the compensation capacitor (C3) and the compensation resistor (R3). This zero is located at: 3 R 3 C 2 1 Z1 f × × π = |
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