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LT1399 Datasheet(PDF) 9 Page - Linear Technology |
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LT1399 Datasheet(HTML) 9 Page - Linear Technology |
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9 / 22 page ![]() LT1228 9 1228fd APPLICATIONS INFORMATION The LT1228 contains two amplifiers, a transconductance amplifier(voltage-to-current)andacurrentfeedbackampli- fier(voltage-to-voltage).Thegainofthetransconductance amplifier is proportional to the current that is externally programmed into Pin 5. Both amplifiers are designed to operate on almost any available supply voltage from 4V (±2V) to 30V (±15V). The output of the transconductance amplifier is connected to the noninverting input of the current feedback amplifier so that both fit into an eight pin package. TRANSCONDUCTANCE AMPLIFIER TheLT1228transconductanceamplifierhasahighimped- ance differential input (Pins 2 and 3) and a current source output (Pin 1) with wide output voltage compliance. The voltage to current gain or transconductance (gm) is set by the current that flows into Pin 5, ISET. The voltage at Pin 5 is two forward biased diode drops above the nega- tive supply, Pin 4. Therefore the voltage at Pin 5 (with respect to V–) is about 1.2V and changes with the log of the set current (120mV/decade), see the characteristic curves.Thetemperaturecoefficientofthisvoltageisabout –4mV/°C (–3300ppm/°C) and the temperature coefficient oftheloggingcharacteristicis3300ppm/°C.Itisimportant that the current into Pin 5 be limited to less than 15mA. THE LT1228 WILL BE DESTROYED IF PIN 5 IS SHORTED TO GROUND OR TO THE POSITIVE SUPPLY. A limiting resistor (2k or so) should be used to prevent more than 15mA from flowing into Pin 5. The small-signal transconductance (gm) is given as gm = 10 • ISET, with gm in (A/V) and ISET in (A).This rela- tionship holds over many decades of set current (see the characteristic curves). The transconductance is inversely proportionaltoabsolutetemperature(–3300ppm/°C).The input stage of the transconductance amplifier has been designed to operate with much larger signals than is pos- sible with an ordinary diff-amp. The transconductance of the input stage varies much less than 1% for differential input signals over a ±30 mV range (see the characteristic curveSmall-SignalTransconductancevsDCInputVoltage). Resistance Controlled Gain If the set current is to be set or varied with a resistor or potentiometeritispossibletousethenegativetemperature coefficient at Pin 5 (with respect to Pin 4) to compensate for the negative temperature coefficient of the transcon- ductance. The easiest way is to use an LT1004-2.5, a 2.5V reference diode, as shown below: Temperature Compensation of gm with a 2.5V Reference LT1228 • TA04 LT1004-2.5 V– gm 5 4 R ISET ISET R Vbe Vbe 2.5V 2Eg The current flowing into Pin 5 has a positive temperature coefficient that cancels the negative coefficient of the transconductance. The following derivation shows why a 2.5Vreferenceresultsinzerogainchangewithtemperature: Sincegm = q kT × ISET 3.87 = 10 •ISET and Vbe = Eg – akT q where a = In cTn Ic ≈ 19.4 at 27°C c = 0.001, n = 3, Ic = 100µA ( ) Eg is about 1.25V so the 2.5V reference is 2Eg. Solving the loop for the set current gives: ISET = 2Eg –2 Eg – akT q R or ISET = 2akT Rq |
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