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MP44011 Datasheet(PDF) 12 Page - Monolithic Power Systems |
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MP44011 Datasheet(HTML) 12 Page - Monolithic Power Systems |
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12 / 15 page ![]() MP44011 – BOUNDARY-MODE PFC CONTROLLER WITH HARMONIC INJECTION MP44011 Rev. 1.01 www.MonolithicPower.com 12 1/12/2012 MPS Proprietary Information. Patent Protected. Unauthorized Photocopy and Duplication Prohibited. © 2012 MPS. All Rights Reserved. DESIGN EXAMPLE FOR FLYBACK PFC WITH MP44011 1. Design Specifications: Input voltage range: VAC=85V-265V Typical mains frequency: fL=50Hz DC output voltage: VOUT=70V Maximum output power: POUT=30W Maximum 2fL output ripple: Δ VO=28V peak-to-peak Minimum switching frequency: fmin=40kHz Harmonic injection ratio: K2=0.75 Reflected voltage: VR=210V Leakage inductance overvoltage: Δ V=100V Expected efficiency: η =85% 2. Preliminary Calculations: Minimum Input Peak Voltage: VPKmin=VACmin× 2 =120V Maximum Input Peak Voltage: VPKmax=VACmax× 2 =375V Maximum Input Power: PIN=POUT/η=35.3W Peak-to-Reflected Voltage Ratio: Kv=VPKmin/VR=0.57 Characteristic functions value: -3 V V V 0.5+1.4 10 K F2(K )= 1+0.815 K -4 V V V 0.424+5.7 10 K F3(K )= 1+0.862 K -3 V V V 0.25-1.5 10 K F4(K )= 1+1.074 K 2.1 Peak Primary Current 1in PKp PKmin V 2K P I1.51A VF2(K ) For MP44011, the coefficient K1 is the peak primary-current ratio compared with the traditional CRM PFC. Here, K1=0.87. 2.2 RMS Primary Current: V2 RMSp PKp F2(K K ) I=I =0.53A 3 2.3 Peak Secondary Current: OUT PKs OUT V V 2P I = =4.29A VK F2(K ) 2.4 RMS Secondary Current: V RMSs PKs F3(K ) I=I =1.03A 3 Power Stage Design 3. Diode Bridge The maximum input RMS current is: in AC _ max AC_min P I0.42(A) V To provide a sufficient margin, select GBU406 (600V/4A). 4. Input Capacitor By setting the coefficient r to 0.1, obtain the input capacitance by using the equation below: AC_max 6 in min AC _ min I C = 0.19 10 (F) 2π fr V Use a 0.22μF tantalum capacitor with a 630V voltage rating as the input capacitor to provide high-frequency energy during switching cycle. 5. Transformer Calculate the primary Inductance using the following: PKmin 2 p 2V min PKp VK L= =1.0mH (1+K K ) f I |
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