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CS5132 Datasheet(PDF) 15 Page - Cherry Semiconductor Corporation |
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CS5132 Datasheet(HTML) 15 Page - Cherry Semiconductor Corporation |
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15 / 19 page ![]() Lower (Synchronous) FET Total Losses = Switch Conduc- tion Losses + Body Diode Losses: PFETL(TOTAL) = 1.27W + 0.16W =1.43W. Calculate Maximum NFET Switch Junction Temperature: TJ = TA + [(PFETL(TOTAL) ) ´QJA ], TJ = 50C + (1.43W) ´ 40ûC/W = 107¡C. Calculate the Gate Driver Losses: PGATE(L) = Q ´ VGATE ´ FSW = 50nC ´ 12V ´ 200KHz = 120mW. Step 7: Free Wheeling Schottky Diode (3.3V Output) The four most application-important characteristics of a Schottky are: 1. Forward voltage drop; 2. Reverse leakage current; 3. Reverse blocking voltage; 4. Maximum permissible junction temperature. We calculate the average Schottky current: IAVG = IOUT ´ (1-D) = 8A ´ 0.34 = 2.72A. We select the Motorola MBRD835L rated at 8A, with 35V DC blocking voltage and 0.51Vforward voltage drop. Neglecting reverse losses, the power dissipation is due to the conduction loss only and can be computed as follows: PSCHOTTKY = VF ´ IAVG, where VF = maximum instantaneous forward voltage; PSCHOTTKY = 0.51V ´ 2.72A = 1.39W. Calculate maximum Schottky junction temperature: TJ = TA + [(PSCHOTTKY ) ´QJA ], TJ = 50C + (1.39W ´ 80ûC/W) = 161¡C. Proper heatsinking (copper pad under Schottky) will be required to reduce Schottky TJ below +125ûC. Step 8: IC Power Dissipation The power dissipation on the IC varies with the MOSFETs used, VCC and the CS5132 operating frequency. This power dissipation is typically dominated by the average gate charge current for the MOSFETs. The average current is approximately: ID = (QGATE(H) + QGATE(L)) ´ FSW1 + QGATE ´ FSW2, where ID = average drive current; QGATE(X) = total gate charge for each MOSFET; FSW1, FSW2 = switching frequencies for the synchronous and non-synchronous sections respectively. The power dissipation for the IC when VCC1 = VCC2 = VCC is: PD = ICC ´ VCC + ID ´ VCC, where ICC = quiescent supply current of the IC (both from VCC1 and VCC2). For the design example in question, PD = 19mA ´ 12V + 0.12W + 0.12W + 0.12W = 0.59W. The junction temperature of the IC is primarily a function of the PCB layout, since most of the heat is removed through the traces connected to the pins of the IC. Adaptive voltage positioning is used to help keep the out- put voltage within specification during load transients. To implement adaptive voltage positioning a ÒDroop ResistorÓ must be connected between the output inductor and output capacitors and load. This resistor carries the full load current and should be chosen so that both DC and AC tolerance limits are met. An embedded PC trace resis- tor has the distinct advantage of near zero cost implemen- tation. However, this droop resistor can vary due to three reasons: 1) the sheet resistivity variation caused by varia- tion in the thickness of the PCB layer; 2) the mismatch of L/W; and 3) temperature variation. 1) Sheet Resistivity For one ounce copper, the thickness variation is typically 1.26 mil to 1.48 mil. Therefore the error due to sheet resis- tivity is: = ±8%. 2) Mismatch due to L/W The variation in L/W is governed by variations due to the PCB manufacturing process. The error due to L/W mis- match is typically 1%. 3) Thermal Considerations Due to I2 ´ R power losses the surface temperature of the droop resistor will increase causing the resistance to increase. Also, the ambient temperature variation will con- tribute to the increase of the resistance, according to the formula: R = R20 [1+ a20(T-20)], 1.48 - 1.26 1.37 ÒDroopÓ Resistor for Adaptive Voltage Positioning and Current Limit Application Information: continued 15 |
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