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LM3429 Datasheet(PDF) 34 Page - Texas Instruments

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Part # LM3429
Description  LM3429Q1 N-Channel Controller for Constant Current LED Drivers
PDF  50 Pages
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Manufacturer  TI1 [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI1 - Texas Instruments

LM3429 Datasheet(HTML) 34 Page - Texas Instruments

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2
9.98V
A
20
k
499
A
20
R
V
OV
HYSO
=
x
:
=
x
=
P
P
=
=
=
A
20
10V
R
OV2
P
:
k
500
V
HYSO
A
20 P
k:
50
1
R
2
UV
=
k:
1
2
R
1
UV =
R
UV1
(
)
R
R
1.24V
UV2
UV1 +
x
V
ON
TURN
=
-
=
V
10.1
=
(
)
k
150
k
21
1.24V
:
+
:
x
k
21 :
V
ON
TURN -
:
=
=
k
2
.
21
-
-
1.24V
V
ON
TURN
x R
1.24V
UV2
=
R
UV1
:
x
k
150
1.24V
-1.24V
10V
3V
A
20
k
150
A
20
R
V
2
UV
HYS
=
x
:
=
x
=
P
P
=
=
=
A
20
3V
R
UV2
P
:
k
150
V
HYS
A
20 P
D1 o 12A, 100V, DPAK
mW
600
mV
600
A
1
V
I
P
FD
D
D
=
x
=
x
=
A
1
I
I
LED
MAX
D
=
=
-
V
91
V
21
V
70
V
V
V
O
MAX
IN
MAX
RD
=
+
=
+
=
-
-
Q1 o 32A, 100V, DPAK
mW
82
m
50
A
28
.
1
R
I
P
2
DSON
2
RMS
T
T
=
:
x
=
x
= -
x
I
RMS
T
=
-
I
LED
D
c
=
x
A
28
.
1
=
0.467
A
1
533
.
0
D
LM3429
SNVS616F – APRIL 2009 – REVISED JANUARY 2010
www.ti.com
A 100V NFET is chosen with a current rating of 32A due to the low RDS-ON = 50 mΩ. Determine IT-RMS and PT:
(125)
(126)
The chosen component from step 9 is:
(127)
10. DIODE
Determine minimum D1 voltage rating and current rating:
(128)
(129)
A 100V diode is chosen with a current rating of 12A and VD = 600 mV. Determine PD:
(130)
The chosen component from step 10 is:
(131)
11. INPUT UVLO
Solve for RUV2:
(132)
The closest standard resistor is 150 k
Ω therefore VHYS is:
(133)
Solve for RUV1:
(134)
The closest standard resistor is 21 k
Ω making VTURN-ON:
(135)
The chosen components from step 11 are:
(136)
12. OUTPUT OVLO
Solve for ROV2:
(137)
The closest standard resistor is 499 k
Ω therefore VHYSO is:
(138)
34
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Copyright © 2009–2010, Texas Instruments Incorporated
Product Folder Links: LM3429



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