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AN2623 Datasheet(PDF) 13 Page - STMicroelectronics |
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AN2623 Datasheet(HTML) 13 Page - STMicroelectronics |
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13 / 25 page ![]() AN2623 Design circuit 13/25 3.5 Feedback loop Since current mode control is employed using the L5991 current mode controller, the power stage of the forward converter exhibits a single output pole due to the output capacitor and load combination, along with a zero due to the ESR of the output capacitor. The goal of the compensator is to achieve a slope of -20 db/decade for the closed loop gain, with a phase margin greater than 45 degrees at the crossover frequency. To achieve good dc regulation, a high low-frequency gain is another requirement for the compensator. For continuous conduction mode operation, the transfer function of the forward converter (power stage) is: Equation 39 where (referring to Figure 4) ● G1o is the power block gain and results in ● R0 is the effective total load resistance of the controlled output defined as ● R9 is the current sense resistance ● n is the turn ratio between the primary and secondary side ● ● In order to reach the objective previously stated at the beginning of this section, the feedback compensation network transfer function, using L5991, is obtained as: Equation 40 where (referring to Figure 4) ● C0 is the feedback block gain and results in ● CTR is the current transfer ratio of the optocoupler ● R5 is the upper resistance of the out voltage divider of feedback net ● R3 is the polarization resistance of the optocoupler ● C8 and R7 are the capacitance and the resistance of the TL431's feedback net ● ω zc is the zero of the feedback net ⇒ to compensate ω p ● ω pc is the pole of the feedback net ⇒ to compensate ω z ● C12 is the capacitor connected at COMP pin of L5991 G 1 s () G 1o 1 s ω z ----- + ⎝⎠ ⎛⎞ 1 s ω p ----- + ⎝⎠ ⎛⎞ --------------------- ⋅ = G 1o nR 0 ⋅ 3R 9 ⋅ ----------------- = R 0 V 2 out P 0 -------------- = ω z 1 ESR cout C out ⋅ ------------------------------------------ = ω p 1 R 0 C out ⋅ -------------------------- = Cs () C 0 1 s ω zc -------- + 1 s ω pc -------- + ------------------ 1 s --- ⋅⋅ = C 0 12 10 3 CTR ⋅⋅ R 5 C 8 R 3 ⋅⋅ ------------------------------------------- = ω zc 1 R 7 C 8 ⋅ --------------------- = ω pc 1 12 10 3 C 12 ⋅⋅ ---------------------------------------- = |
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