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ADG466 Datasheet(PDF) 5 Page - Analog Devices |
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ADG466 Datasheet(HTML) 5 Page - Analog Devices |
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5 / 8 page ![]() ADG466/ADG467 –5– REV. 0 CIRCUIT INFORMATION Figure 7 below shows a simplified schematic of a channel protector circuit. The circuit is made up of four MOS transis- tors—two NMOS and two PMOS. One of the PMOS devices does not lie directly in the signal path but is used to connect the source of the second PMOS device to its backgate. This has the effect of lowering the threshold voltage and so increasing the input signal range of the channel for normal operation. The source and backgate of the NMOS devices are connected for the same reason. During normal operation the channel protectors have a resistance of 60 Ω typ. The channel protectors are very low power devices, and even under fault conditions the supply current is limited to sub micro-ampere levels. All transistors are dielectrically isolated from each other using a trench isolation method. This makes it impossible to latch up the channel protectors. For an explanation, see “Trench Isolation” section. NMOS PMOS PMOS NMOS VDD VSS VSS VDD Figure 7. The Channel Protector Circuit Overvoltage Protection When a fault condition occurs on the input of a channel protector, the voltage on the input has exceeded some threshold voltage set by the supply rail voltages. The threshold voltages are related to the supply rails as follows. For a positive overvolt- age, the threshold voltage is given by VDD – VT where VTN is the threshold voltage of the NMOS transistor (1.5 V typ). In the case of a negative overvoltage the threshold voltage is given by VSS – VTP where VTP is the threshold voltage of the PMOS device (2 V typ). If the input voltage exceeds these threshold voltages, the output of the channel protector (no load) is clamped at these threshold voltages. However, the channel protector output will clamp at a voltage that is inside these thresholds if the output is loaded. For example with an output load of 1 k Ω, V DD = 15 V and a positive overvoltage. The output will clamp at VDD – VTN – ∆V = 15 V – 1.5 V – 0.6 V = 12.9 V where ∆V is due to I × R voltage drop across the channels of the MOS devices (see Figure 9). As can be seen from Figure 9, the current during fault condition is determined by the load on the output (i.e., VCLAMP/RL). However, if the supplies are off, the fault current is limited to the nano-ampere level. Figures 8, 10 and 11 show the operating conditions of the signal path transistors during various fault conditions. Figure 8 shows how the channel protectors operate when a positive overvoltage is applied to the channel protector. NMOS PMOS NMOS VDD (+15V) VSS (–15V) VDD (+15V) POSITIVE OVERVOLTAGE (+20V) VDD – VTN* (+13.5V) *VTN = NMOS THRESHOLD VOLTAGE (+1.5V) NON- SATURATED NON- SATURATED SATURATED Figure 8. Positive Overvoltage on the Channel Protector The first NMOS transistor goes into a saturated mode of operation as the voltage on its Drain exceeds the Gate voltage (VDD) – the threshold voltage (VTN). This situation is shown in Figure 9. The potential at the source of the NMOS device is equal to VDD – VTN. The other MOS devices are in a nonsaturated mode of operations. When a negative overvoltage is applied to the channel protector circuit, the PMOS transistor enters a saturated mode of opera- tion as the drain voltage exceeds VSS – VTP. See Figure 10 be- low. As in the case of the positive overvoltage, the other MOS devices are nonsaturated. NMOS PMOS NMOS VDD (+15V) VSS (–15V) VDD (+15V) NEGATIVE OVERVOLTAGE (–20V) VSS – VTP* (–13V) *VTP = PMOS THRESHOLD VOLTAGE (–2V) NEGATIVE OVERVOLTAGE (–20V) NON- SATURATED NON- SATURATED SATURATED Figure 10. Negative Overvoltage on the Channel Protector VS N + (VDD =15V) VD P – N + N + (+20V) (+13.5V) OVERVOLTAGE OPERATION (SATURATED) VT = 1.5V (VG – VT = 13.5V) VG EFFECTIVE SPACE CHARGE REGION N CHANNEL NMOS PMOS NONSATURATED OPERATION RL ∆V IOUT VCLAMP Figure 9. Positive Overvoltages Operation of the Channel Protector OBSOLETE |
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