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LT1576CS8 Datasheet(PDF) 25 Page - Linear Technology |
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LT1576CS8 Datasheet(HTML) 25 Page - Linear Technology |
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25 / 28 page ![]() 25 LT1576/LT1576-5 APPLICATIONS INFORMATION IA CONT = () ( ) + () ++ () = 55 15 4 5 55 5 550 5 038 22 .. .. . . This says that discontinuous mode can be used and the minimum inductor needed is found from: LH MIN = ()( ) () = 25 0 25 200 10 1 5 56 3 2 . •. .µ In practice, the inductor should be increased by about 30% over the calculated minimum to handle losses and varia- tions in value. This suggests a minimum inductor of 7.3 µH for this application, but looking at the ripple voltage chart shows that output ripple voltage could be reduced by a fac- tor of two by using a 30 µHinductor.Thereisnoruleofthumb here to make a final decision. If modest ripple is needed and the larger inductor does the trick, go for it. If ripple is non- critical use the smaller inductor. If ripple is extremely criti- cal, a second filter may have to be added in any case, and the lower value of inductance can be used. Keep in mind that the output capacitor is the other critical factor in deter- mining output ripple voltage. Ripple shown on the graph (Figure 16) is with a capacitor’s ESR of 0.1 Ω. This is rea- sonable for AVX type TPS “D” or “E” size surface mount solid tantalum capacitors, but the final capacitor chosen must be looked at carefully for ESR characteristics. inductor is therefore typically based on ensuring that peak switch current rating is not exceeded. This gives the lowest value of inductance that can be used, but in some cases (lower output load currents) it may give a value that creates unnecessarily high output ripple voltage. A com- promise value is often chosen that reduces output ripple. As you can see from the graph, large inductors will not give arbitrarily low ripple, but small inductors can give high ripple. The difficulty in calculating the minimum inductor size needed is that you must first know whether the switcher will be in continuous or discontinuous mode at the critical point where switch current is 1.5A. The first step is to use the following formula to calculate the load current where the switcher must use continuous mode. If your load current is less than this, use the discontinuous mode formula to calculate minimum inductor needed. If load current is higher, use the continuous mode formula. Output current where continuous mode is needed: I VI VV VV V CONT IN P IN OUT IN OUT F = () ( ) + () ++ () 22 4 Minimum inductor discontinuous mode: L VI fI MIN OUT OUT P = ()( ) ()( ) 2 2 Minimum inductor continuous mode: L VV fV V I I VV V MIN IN OUT IN OUT P OUT OUT F IN = ()( ) () + () −+ + () 21 For the example above, with maximum load current of 0.25A: |
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