AD7475ARM datasheet(5/16 Pages) AD

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REV. A

AD7475/AD7495

–5–

SCLK

SDATA

FOUR LEADING ZEROS

THREE-STATE

tQUIET

tCONVERT

THREE-STATE

DB11

DB10

DB2

DB0

DB1

Figure 1. Serial Interface Timing Diagram

Timing Example 1

Having fSCLK = 20 MHz and a throughput of 1 MSPS gives a cycle

time of t2 + 12.5(1/fSCLK) + tACQ = 1

µs. With t2 = 10 ns min, this

leaves tACQ to be 365 ns. This 365 ns satisfies the requirement of

300 ns for tACQ. From Figure 2, tACQ comprises of 2.5(1/fSCLK) + t8

+ tQUIET, where t8 = 45 ns. This allows a value of 195 ns for tQUIET,

satisfying the minimum requirement of 100 ns.

Timing Example 2

Having fSCLK = 5 MHz and a throughput of 315 KSPS, gives a

cycle time of t2 + 12.5(1/fSCLK) + tACQ = 3.174 s.

With t2 = 10 ns min, this leaves tacq to be 664 ns. This 664 ns

satisfies the requirement of 300 ns for tACQ. From Figure 2, tACQ

is comprised of 2.5(1/fSCLK) + t8 + tQUIET, t8 = 45 ns. This allows

a value of 119 ns for tQUIET satisfying the minimum requirement

of 100 ns. As in this example and with other slower clock values,

the signal may already be acquired before the conversion is

complete, but it is still necessary to leave 100 ns minimum

tQUIET between conversions. In Example 2 the signal should be

fully acquired at approximately Point C in Figure 2.

SCLK

tQUIET

tCONVERT

45ns

tACQUISITION

12.5 (1/fSCLK)

10ns

1/THROUGHPUT

Figure 2. Serial Interface Timing Example

200 A

IOL

200 A

IOH

50pF

TO OUTPUT

1.6V

Figure 3. Load Circuit for Digital Output Timing Specifications

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