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THS6007 Datasheet(PDF) 13 Page - Texas Instruments |
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THS6007 Datasheet(HTML) 13 Page - Texas Instruments |
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13 / 36 page  THS6007 DUAL DIFFERENTIAL LINE DRIVERS AND LOW-POWER RECEIVERS SLOS334– DECEMBER 2000 13 POST OFFICE BOX 655303 • DALLAS, TEXAS 75265 TYPICAL CHARACTERISTICS (DRIVER) Figure 22 f – Frequency – Hz OUTPUT AMPLITUDE vs FREQUENCY –10 10M 100k 20 30 500M 40 70 1M 100M 50 60 Gain = 1000 0 10 VCC = ± 5 V RG =10 Ω RL = 25 Ω VO = 2 V Gain = 100 Figure 23 f – Frequency – Hz OUTPUT AMPLITUDE vs FREQUENCY –10 10M 100k 20 30 500M 40 70 1M 100M 50 60 Gain = 1000 0 10 VCC = ± 5 V RG =10 Ω RL = 25 Ω VO = 2 V Gain = 100 Figure 24 NORMALIZED OUTPUT RESPONSE vs FREQUENCY 1M f – Frequency – Hz 100k 10M 100M 500M –3 –5 –7 –9 –4 –6 –8 –1 0 –2 1 RL = 200 Ω RL = 100 Ω RL = 25 Ω VCC = ±15 V RF = 1 kΩ Gain = 1 VI = 200 mV RL = 50 Ω Figure 25 NORMALIZED OUTPUT RESPONSE vs FREQUENCY 1M f – Frequency – Hz 100k 10M 100M VCC = ±15 V RF = 1 kΩ Gain = 2 VI = 200 mV 500M –3 –5 –7 –9 –4 –6 –8 –1 0 –2 1 RL = 200 Ω RL = 100 Ω RL = 50 Ω RL = 25 Ω Figure 26 NORMALIZED OUTPUT RESPONSE vs FREQUENCY 1M f – Frequency – Hz 100k 10M 100M VCC = ±15 V RL = 100 Ω Gain = 1 VI = 200 mV 500M –1 –3 –5 –7 –2 –4 –6 1 2 0 3 RF = 620 Ω RF = 820 Ω RF = 1 kΩ Figure 27 NORMALIZED OUTPUT RESPONSE vs FREQUENCY 1M f – Frequency – Hz 100k 10M 100M VCC = ±15 V RL = 100 Ω Gain = 2 VI = 200 mV 500M –1 –3 –5 –2 –4 –6 1 2 0 3 RF = 430 Ω RF = 1 kΩ RF = 620 Ω Figure 28 f – Frequency – Hz SMALL AND LARGE SIGNAL FREQUENCY RESPONSE –27 –30 10M 100k –18 –15 500M –12 –3 1M 100M –9 –6 VI = 500 mV –24 –21 Gain = 1 VCC = ± 15 V RF = 820 Ω RL = 25 Ω VI = 250 mV VI = 125 mV VI = 62.5 mV Figure 29 f – Frequency – Hz SMALL AND LARGE SIGNAL FREQUENCY RESPONSE –21 –24 10M 100k –12 –9 500M –6 3 1M 100M –3 0 VI = 500 mV –18 –15 Gain = 2 VCC = ± 15 V RF = 680 Ω RL = 25 Ω VI = 250 mV VI = 125 mV VI = 62.5 mV Figure 30 f – Frequency – Hz SINGLE–ENDED HARMONIC DISTORTION vs FREQUENCY –90 –100 1M –60 100k –80 –70 10M –50 –40 2nd Harmonic 3rd Harmonic VCC = ± 15 V Gain = 2 RF = 680 Ω RL = 25 Ω VO(PP) = 2V |
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