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RT9911 Datasheet(PDF) 28 Page - Richtek Technology Corporation |
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RT9911 Datasheet(HTML) 28 Page - Richtek Technology Corporation |
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28 / 32 page ![]() RT9911 28 DS9911-04 August 2007 www.richtek.com Asyn-boost in CCM : We call it CCM because inductor current is always continuous in operation. The benefit of designing in CCM is lower VOUT and inductor current ripple and higher efficiency from the lower coil loss, but with the expense of larger inductor size and cost and the control loop comes with a RHPZ (Right Hand Plan Zero) and a conjugate double pole in the frequency domain to worry about. The fixed parameters for CH4 asyn-boost in CCM compensation are as follows : Transconductance (from FB to COMP), GM = 200us Internal voltage ramp to decide duty cycle, VP = 1V Feedback voltage, VFB = FB = 1V The input parameters for CH4 asyn-boost in CCM compensation are as follows: R1, the voltage divider resistor in between VOUT and FB. VIN, input voltage. VOUT, desired output voltage IOUT(MAX.), maximum output load IOUT(MIN.), minimum output laod fOSC, operating frequency The input parameters for CH4 asyn-boost in DCM compensation are as follows : R1, the voltage divider resistor in between VOUT and FB. VIN, input voltage. VOUT, desired output voltage IOUT(MAX.), maximum output load fOSC, operating frequency L, inductance COUT, output capacitance. This compensation is based on ceramic output capacitor. RESR, ESR (Equivalent Series Resistance) of COUT (ceramic output capacitor) The results we will get for CH4 asyn-boost in DCM compensation are as follows : R2, the voltage divider resistor in between FB and ground. CF, feedforward capacitor in parallel with R1. RC, compensation resistor on COMP pin. CC, compensation capacitor in series with RC and connect to ground CP, connect in between COMP pin and ground. (Can be ignored if CP < 10pF) The major steps for getting above results : 1. 2. Select suitable inductor to ensure IOUT(MIN.) works in DCM, which is let inductor current falls to zero on each switch cycle. 3. Set fC sufficient below fOSC. For example: 4. 5. which is duty to VOUT transfer function. 6. 7. Find ffz, zero and ffp, pole ratio of voltage divider with CF. 8. Get CF by placing ffp on fC and ffz therefore on . 9. Evaluate CP. CP is for canceling the zero from COUT (ceramic output capacitor). FB OUT FB V - V V x R1 R2 = OSC OUT(MAX.) IN f x I x 2 D) - (1 x D x V L < lower or 10 f f OSC C = . I V R , V V M where , C x R x 1) - (M x 2 1 - M x 2 f : pole load the Find OUT(MAX.) OUT LOAD IN OUT OUT LOAD LP = = = π , 1 - M x 2 1 - M x D V x 2 G where , G x GM x V f f R Get OUT dod dod P LP C C = = OUT IN V V - 1 cycle duty D = = pole. load zero comp letting by R R x C C Get C LOAD OUT C = = FB OUT V V ffz ffp ratio = = ratio fC 10pF. C if ignore be can C . R R x C C P P C ESR OUT P < = . ratio f ff where , R1 ff 2 1 C C Z Z F = × × = π |
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