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HC5526IP Datasheet(PDF) 10 Page - Intersil Corporation |
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HC5526IP Datasheet(HTML) 10 Page - Intersil Corporation |
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10 / 18 page ![]() 66 Therefore: Equation 16 can now be used to match the SLIC’s impedance to any known line impedance (ZTR). Example: Calculate ZT to make ZTR = 600Ω in series with 2.16µF. RF = 20Ω. ZT = 560kΩ in series with 2.16nF. (AC) 2-Wire to 4-Wire Gain The 2-wire to 4-wire gain is equal to VTX/ VTR. From Equations 9 and 10 with VRX = 0: (AC) 4-Wire to 2-Wire Gain The 4-wire to 2-wire gain is equal to VTR/VRX. From Equations 9, 10 and 11 with EG = 0: For applications where the 2-wire impedance (ZTR, Equation 15) is chosen to equal the line impedance (ZL), the expression for A4-2 simplifies to: (AC) 4-Wire to 4-Wire Gain The 4-wire to 4-wire gain is equal to VTX/VRX. From Equations 9, 10 and 11 with EG = 0: Transhybrid Circuit The purpose of the transhybrid circuit is to remove the receive signal (VRX) from the transmit signal (VTX), thereby preventing an echo on the transmit side. This is accomplished by using an external op amp (usually part of the CODEC) and by the inversion of the signal from the 4-wire receive port (RSN) to the 4-wire transmit port (VTX). Figure 17 shows the transhybrid circuit. The input signal will be subtracted from the output signal if I1 equals I2. Node analysis yields the following equation: The value of ZB is then: Where VRX/VTX equals 1/ A4-4. Therefore: Example: Given: RTX = 20kΩ, ZRX = 280kΩ, ZT = 562kΩ (standard value), RF = 20Ω and ZL = 600Ω. The value of ZB = 18.7kΩ. VTX RSN TIP RING IM ZTR VTR EG VTX IM 1000 VTX ZRX 1 HC5526 RF RF A = 4 + - + - + - + - ZT + - VRX + - A = 250 A = 250 IM ZL FIGURE 16. SIMPLIFIED AC TRANSMISSION CIRCUIT Z T 1000 Z TR 2R F – () • = (EQ. 16) Z T 1000 600 1 j ω 2.16 • 10 6 – • ----------------------------------------- 220 • – + • = A 24 – V TX V TR ----------- Z T 1000 ⁄ Z T 1000 ⁄ 2R F + ------------------------------------------ == (EQ. 17) A 42 – V TR V RX ----------- Z T Z RX ----------- – Z L Z T 1000 ------------- 2R F Z L ++ -------------------------------------------- • == (EQ. 18) A 42 – Z T Z RX ----------- – 1 2 --- • = (EQ. 19) A 44 – V TX V RX ----------- Z T Z RX ----------- – Z L 2R F + Z T 1000 ------------- 2R F Z L ++ -------------------------------------------- • == (EQ. 20) V TX R TX ----------- V RX Z B ----------- + 0 = (EQ. 21) Z B R – TX V RX V TX ----------- • = (EQ. 22) Z B R TX Z RX Z T ----------- • Z T 1000 ------------- 2R F Z L ++ Z L 2R F + -------------------------------------------- • = (EQ. 23) HC5526 |
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