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SP6652 Datasheet(PDF) 7 Page - Sipex Corporation |
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SP6652 Datasheet(HTML) 7 Page - Sipex Corporation |
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7 / 11 page ![]() 7 Date:5/25/04 SP6652 1A, High Efficiency, High Frequency Current Mode PWM Buck Regulator © Copyright 2004 Sipex Corporation Voltage Loop and Compensation in PWM Mode The voltage loop section of the circuit consists of the error amplifier and the translator circuits (see functional diagram). The input of the volt- age loop is the 0.75V reference voltage minus the divided down output voltage at the feedback pin. The output of the error amplifier is trans- lated from a ground referred signal (the COMP node) to a power input voltage referred signal. The output of the voltage loop is fed to the positive terminal of the Current Loop compara- tor, and represents the peak inductor current necessary to close the loop. The total power supply loop is compensated with a series RC network connected from the COMP pin to ground. Compensation is simple due to current-mode control. The modulator has two dominant poles: one at a low frequency, and one above the crossover frequency of the loop, as seen in the graph below, Linearized Modula- tor Frequency Response vs. Inductor Value. The low frequency pole for L1=5 µH is 4kHz, the second pole is 500kHz, and the gain-band- width is 20kHz. The total loop crossover fre- quency is chosen to be 200kHz, which is 1/6th of the clock frequency. This sets the 2nd modula- tor pole at 2.5 times the crossover frequency. Therefore the gain of the error amplifier can be 200kHz/20kHz = 10 at the first modulator pole of 4kHz. The error amp transconductance is 1mS, so this sets the RZ resistor value in the compensation network at 10/1mS = 10k Ω. The zero frequency is placed at the first pole to provide at total system response of -20dB/de- cade (the zero from the error amp cancels the first modulator pole, leaving the 1 pole rolloff from the error amp pole). The compensation capacitor becomes: Cc = 1/(2* π*Rz*pole1) = 1/(6.28*10kΩ*4kHz) = 4nF DETAIL DESCRIPTION: Contunued L1VAL 2u 3u 4u 5u 6u 7u 8u 9u 10u Mod_pole1 Mod_pole2 Gbw_modfb 0 4K 8K 12K 16K 20K 1 0 0.4M 0.8M 1.2M 1.6M 2.0M 2 0 10K 20K 30K 40K 50K 3 >> 1 2 3 Conditions: V IN=5V, VOUT=3.3V, fCLK=1.2MHz, COUT=10µF, and MCV=132mV/µs. The inductor is varied from 2µH to 10µH Linearized Modulator Frequency Response vs. Inductor Value. |
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