| Electronic Components Datasheet Search |
|
OPA690 Datasheet(PDF) 19 Page - Texas Instruments |
|
|
|
|||||||||||||||||||||||||||||
OPA690 Datasheet(HTML) 19 Page - Texas Instruments |
|
19 / 27 page ![]() OPA2613 SBOS249D − JUNE 2003− REVISED APRIL 2004 www.ti.com 19 With the previous information available, it is now possible to select a supply voltage and the turns ratio desired for the transformer as well as calculate the headroom for the OPA2613. The model (shown in Figure 8) can be described with the following set of equations: 1. First, as available output swing: V PP + V CC * (V1 ) V2) * I P (R 1 ) R 2) 2. Or as required supply voltage: V CC + VPP ) (V1 ) V2) ) I P (R 1 ) R 2) The minimum supply voltage for a power and load requirement is given by Equation 11. V O R 1 V 1 +V CC R 2 V 2 I P Figure 8. Line Driver Headroom Model V1, V2, R1, and R2 are given in Table 1 for both +12V and +5V operation. Table 1. Line Driver Headroom Model Values V1 R1 V2 R2 +5V 1.0V 2 Ω 1.0V 5.5 Ω +12V 1.0V 2 Ω 1.0V 5.5 Ω TOTAL DRIVER POWER FOR xDSL APPLICATIONS The total internal power dissipation for the OPA2613 in an xDSL line driver application will be the sum of the quiescent power and the output stage power. The OPA2613 holds a relatively constant quiescent current versus supply voltage—giving a power contribution that is simply the quiescent current times the supply voltage used (the supply voltage will be greater than the solution given in Equation 12). The total output stage power may be computed with reference to Figure 9. R T +V CC I AVG = I P C F Figure 9. Output Stage Power Model The two output stages used to drive the load of Figure 7 can be seen as an H-Bridge in Figure 9. The average current drawn from the supply into this H-Bridge and load will be the peak current in the load given by Equation 10 divided by the crest factor (CF) for the xDSL modulation. This total power from the supply is then reduced by the power in RT to leave the power dissipated internal to the drivers in the four output stage transistors. That power is simply the target line power used in Equation 5 plus the power lost in the matching elements (RM). In the examples here, a perfect match is targeted giving the same power in the matching elements as in the load. The output stage power is then set by Equation 13. P OUT + I P CF V CC * 2PL The total amplifier power is then: P TOT + Iq V CC ) I P CF V CC * 2PL For the ADSL CPE upstream driver design of Figure 6, the peak current is 150mA for a signal that requires a crest factor of 5.33 with a target line power of 13dBm into 100 Ω (20mW). With a typical quiescent current of 12mA and a nominal supply voltage of +12V, the total internal power dissipation for the solution of Figure 6 will be: P TOT + 12mA(12V) ) 150mA 5.33 (12V) * 2(20mW) + 400mW (11) (12) (13) (14) (15) |
|
Link URL |
| Does ALLDATASHEET help your business so far? [ DONATE ] |
About Alldatasheet | Advertisement | Contact us | Privacy Policy | Link to Datasheet | Link Exchange | Manufacturer List All Rights Reserved©Alldatasheet.com |
| Russian : Alldatasheetru.com | Korean : Alldatasheet.co.kr | Spanish : Alldatasheet.es | French : Alldatasheet.fr | Italian : Alldatasheetit.com Portuguese : Alldatasheetpt.com | Polish : Alldatasheet.pl | Vietnamese : Alldatasheet.vn Indian : Alldatasheet.in | Mexican : Alldatasheet.com.mx | British : Alldatasheet.co.uk | New Zealand : Alldatasheet.co.nz |
|
Family Site : ic2ic.com |
icmetro.com |