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LM2576 Datasheet(PDF) 18 Page - ON Semiconductor |
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LM2576 Datasheet(HTML) 18 Page - ON Semiconductor |
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18 / 26 page ![]() LM2576 http://onsemi.com 18 beyond approximately 6.0 in2 (4000 mm2) will not improve heat dissipation significantly. If further thermal improvements are needed, double sided or multilayer PC boards with large copper areas should be considered. In order to achieve the best thermal performance, it is highly recommended to use wide copper traces as well as large areas of copper in the printed circuit board layout. The only exception to this is the OUTPUT (switch) pin, which should not have large areas of copper (see page 8 ‘PCB Layout Guideline’). Thermal Analysis and Design The following procedure must be performed to determine whether or not a heatsink will be required. First determine: 1. PD(max) maximum regulator power dissipation in the application. 2. TA(max) maximum ambient temperature in the application. 3. TJ(max) maximum allowed junction temperature (125 °C for the LM2576). For a conservative design, the maximum junction temperature should not exceed 110 °C to assure safe operation. For every additional +10 °C temperature rise that the junction must withstand, the estimated operating lifetime of the component is halved. 4. RqJC package thermal resistance junction−case. 5. RqJA package thermal resistance junction−ambient. (Refer to Maximum Ratings on page 2 of this data sheet or RqJC and RqJA values). The following formula is to calculate the approximate total power dissipated by the LM2576: PD = (Vin x IQ) + d x ILoad x Vsat where d is the duty cycle and for buck converter d + ton T + V O V in , IQ (quiescent current) and Vsat can be found in the LM2576 data sheet, Vin is minimum input voltage applied, VO is the regulator output voltage, ILoad is the load current. The dynamic switching losses during turn−on and turn−off can be neglected if proper type catch diode is used. Packages Not on a Heatsink (Free−Standing) For a free−standing application when no heatsink is used, the junction temperature can be determined by the following expression: TJ = (RqJA) (PD) + TA where (RqJA)(PD) represents the junction temperature rise caused by the dissipated power and TA is the maximum ambient temperature. Packages on a Heatsink If the actual operating junction temperature is greater than the selected safe operating junction temperature determined in step 3, than a heatsink is required. The junction temperature will be calculated as follows: TJ = PD (RqJA + RqCS + RqSA) + TA where RqJC is the thermal resistance junction−case, RqCS is the thermal resistance case−heatsink, RqSA is the thermal resistance heatsink−ambient. If the actual operating temperature is greater than the selected safe operating junction temperature, then a larger heatsink is required. Some Aspects That can Influence Thermal Design It should be noted that the package thermal resistance and the junction temperature rise numbers are all approximate, and there are many factors that will affect these numbers, such as PC board size, shape, thickness, physical position, location, board temperature, as well as whether the surrounding air is moving or still. Other factors are trace width, total printed circuit copper area, copper thickness, single− or double−sided, multilayer board, the amount of solder on the board or even color of the traces. The size, quantity and spacing of other components on the board can also influence its effectiveness to dissipate the heat. Figure 26. Inverting Buck−Boost Develops −12 V D1 1N5822 L1 68 mH Output 2 4 Feedback 12 to 40 V Unregulated DC Input Cin 100 mF 1 5 3ON/OFF GN D +Vin −12 V @ 0.7 A Regulated Output Cout 2200 mF LM2576−12 ADDITIONAL APPLICATIONS Inverting Regulator An inverting buck−boost regulator using the LM2576−12 is shown in Figure 26. This circuit converts a positive input voltage to a negative output voltage with a common ground by bootstrapping the regulators ground to the negative output voltage. By grounding the feedback pin, the regulator senses the inverted output voltage and regulates it. In this example the LM2576−12 is used to generate a −12 V output. The maximum input voltage in this case cannot exceed +28 V because the maximum voltage appearing across the regulator is the absolute sum of the input and output voltages and this must be limited to a maximum of 40 V. |
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