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LM3495 Datasheet(PDF) 17 Page - National Semiconductor (TI) |
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LM3495 Datasheet(HTML) 17 Page - National Semiconductor (TI) |
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17 / 26 page ![]() Design Considerations (Continued) minimum inductance must be used based on the R DSON of the low-side FET and the desired switching frequency. As with switching frequency, the inductance used is a tradeoff between size and cost. Larger inductance means low current ripple and hence low output voltage ripple. However, less inductance results in smaller, less expensive devices. An inductance that gives a ripple current of 30% to 40% of the maximum load current is a good starting point ( ∆i O = 30% to 40%*I O). Minimum inductance should be calculated from this value, using the maximum input voltage, as: By calculating in terms of amperes, volts, and megahertz, the inductance value will come out in micro henries. The second minimum inductance equation specific to the LM3495 is: By calculating in terms of milliohms and kilohertz the induc- tance value will come out in micro henries. For this design: Whichever equation gives the higher value for inductance is the one which should be followed. The second criterion for selecting an inductor is the peak current carrying capability. This is the level above which the inductor will saturate. In saturation the inductance drops off severely, often to 20% to 30% of the rated value. In a buck converter, peak current, I PK, is equal to the maximum load current plus one half of the ripple current. For this example: I PK = 10A + 1.5A = 11.5A Hence an inductor must be selected that has a peak current rating greater than 11.5A and an average current rating greater than 10A. To ensure a robust design, the inductor selected should maintain approximately 50% of its rated inductance during the worst-case peak current from an out- put short circuit. For a low-side current limit the peak current during an output short circuit can be estimated as I CL plus ∆i (O-MAX). ∆i (O-MAX) is calculated by substituting zero for output voltage in the expression for ∆i O. Inductor core ma- terials with soft saturation characteristics are preferred. One inductor that meets the peak current guidelines is an off-the- shelf 1.0 µH component that can handle a peak current of 18A and an average current of 14A. The inductor current ripple and peak inductor current should be recalculated for the selected inductance value, L ACTUAL, by rearranging the equation for minimum inductance: OUTPUT CAPACITOR The output capacitor in a switching regulator is selected on the basis of capacitance, equivalent series resistance (ESR), size, and cost. An important specification in switching con- verters is the output ripple voltage, ∆v O. At 500 kHz the impedance of most capacitors is very small compared to ESR, hence ESR becomes the main selection guide. In this design the load requires a 1% ripple, which results in a ∆v O of 10 mV P-P. Maximum ESR is then: ESR MAX is 10 m Ω. Multi-layer ceramic, aluminum electro- lytic, tantalum, solid aluminum, organic, and niobium capaci- tors are all popular in switching converters. Generally, by the time enough capacitors have been paralleled to obtain the desired ESR, the bulk capacitance is more than enough to supply the load current during a transient from no-load to full load. In this example the load could transition quickly from 0A to 5A, (or from 5A to 0A), so moderate bulk capacitance is needed. Two MLCC capacitors rated 100 µF, 6.3V each with ESR of 3 m Ω will work well. VLIN5 DECOUPLING CAPACITOR The VLIN5 pin should always be decoupled with a 2.2 µF, 10V-rated ceramic capacitor placed as close as possible to the VLIN5 and PGND pins of the LM3495. The decoupling capacitor should have a minimum X5R or X7R type dielectric to ensure that the capacitance remains stable over the ex- pected voltage and temperature range. INPUT CAPACITOR The input capacitors to a buck regulator are used to smooth the large current pulses drawn by the inductor and load when the high-side FET is on. Due to this large AC stress, input capacitors are usually selected on the basis of their AC rms current rating rather than bulk capacitance. Low ESR is beneficial because it reduces the power dissipation in the capacitors. Although any of the capacitor types mentioned in the Output Capacitor section can be used, MLCCs are com- mon because of their low ESR and because in general the input to a buck converter does not require as much bulk capacitance as the output. Input current, I rms, can be calcu- lated using the following equation: A good estimate for the maximum AC rms current is one-half of the maximum load current. For this example, the rms input current can be estimated as 3.5A. Regardless of the type and number of capacitors used, every design will benefit www.national.com 17 |
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