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PCK9448 Datasheet(PDF) 11 Page - NXP Semiconductors |
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PCK9448 Datasheet(HTML) 11 Page - NXP Semiconductors |
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11 / 20 page ![]() 9397 750 12534 © Koninklijke Philips Electronics N.V. 2005. All rights reserved. Product data sheet Rev. 01 — 29 November 2005 11 of 20 Philips Semiconductors PCK9448 3.3 V/2.5 V LVCMOS 1 : 12 clock fan-out buffer The waveform plots of Figure 13 show simulation results of an output driving a single line versus two lines. In both cases the drive capability of the PCK9448 output buffer is more than sufficient to drive 50 Ω transmission lines on the incident edge. Note from the delay measurement in the simulations a delta of only 43 ps exists between the two differently loaded outputs. This suggests that the dual line driving need not be used exclusively to maintain the tight output-to-output skew of the PCK9448. The output waveform in Figure 13 shows a step in the waveform; this step is caused by the impedance mismatch seen looking into the driver. The parallel combination of the 33 Ω series resistor plus the output impedance does not match the parallel combination of the line impedances. The voltage wave launched down the two lines will equal: At the load end the voltage will double, due to the near unity reflection coefficient, to 2.5 V. It will then increment towards the quiescent 3.0 V in steps separated by one round trip delay (in this case 4.0 ns). Since this step is well above the threshold region it will not cause any false clock triggering, however designers may be uncomfortable with unwanted reflections on the line. To better match the impedances when driving multiple lines, the situation in Figure 14 should be used. In this case the series terminating resistors are reduced such that when the parallel combination is added to the output buffer impedance the line impedance is perfectly matched. Fig 13. Single versus dual line termination waveforms V L V S Z o R s R o Z o ++ ------------------------------ = Z o 50 Ω 50 Ω R s 33 Ω 33 Ω R o 17 Ω = || = || = V L 3.0 25 16.5 17 25 ++ ----------------------------------- 1.28 V = = time (ns) 016 12 48 002aaa679 3.0 voltage (V) −0.5 0 1.0 2.0 IN OutA td = 3.8956 ns OutB td = 3.9386 ns |
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