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OPA623AP Datasheet(PDF) 11 Page - Texas Instruments

Part # OPA623AP
Description  OPERATIONAL AMPLIFIER
PDF  16 Pages
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Manufacturer  TI1 [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI1 - Texas Instruments

OPA623AP Datasheet(HTML) 11 Page - Texas Instruments

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11
®
OPA623
reduce the internal thermal rise, resulting in cooler, more
reliable operation. At extreme temperatures and under full
load conditions a heat sink is necessary. The internal power
dissipation is given by the equation P
D = PDQ + PDL, (PDQ
is the quiescent power dissipation and PDL is the power
dissipation in the output stage due to the load). Although the
PDQ is very low (40mW at VCC = ±5V), care should be taken
when a signal is applied. For high-speed op amps, a more
precise approach to determine power consumption is to
measure the average total quiescent current for several
typical load conditions. The power consumption of the
OPA623 is influenced by the kind of signal, the applied
signal frequency, the output voltage, load resistor, and the
repetition rate of the signal transitions. Figure 8 shows the
average supply current versus the frequency of an applied
sine wave for various output voltages. Figure 9 illustrates the
average supply current versus the repetition frequency of an
applied square wave signal.
FIGURE 5. Open-Loop Gain vs R2 || R1.
50
40
30
20
10
0
–10
–20
–30
Frequency (Hz)
100k
1M
10M
100M
1G
300
Ω
150
Ω
27
Ω
1M
10M
100M
1G
Frequency (Hz)
FREQUENCY RESPONSE vs C
LOAD
G
CL = +2V/V, VIN = 1.4Vp-p
10pF
22pF
47pF
100k
2pF
51
Ω
DUT
50
Ω
R
2
C
L
R
1
3
2
6
R
1
300
Ω
270
Ω
240
Ω
120
Ω
R
2
300
Ω
270
Ω
240
Ω
120
Ω
C
L
2pF
10pF
22pF
47pF
FIGURE 7. Frequency Response vs CLOAD.
10k
100k
1M
10M
100M
1G
Frequency (Hz)
50
45
40
35
30
25
20
15
10
5
0
Sine Curve
R
L = 100Ω
G = +2V/V
C
L = 2pF
5.0Vp-p
2.8Vp-p
1.4Vp-p
0.2Vp-p
FIGURE 8. Average Supply Current vs Frequency
(sinewave).
FIGURE 6. Optimum Frequency Response vs Closed-Loop
Gain.
20
15
10
5
0
–5
–10
–15
–20
–25
–30
Frequency (Hz)
100k
1M
10M
100M
1G
+10V/V
+2V/V
+1V/V
–1V/V
25
20
15
10
5
0
10k
100k
1M
10M
100M
Frequency (Hz)
5.0Vp-p
2.8Vp-p
1.4Vp-p
0.2Vp-p
G = +2V/V
C
L = 2pF
R
L = 100Ω
FIGURE 9. Average Supply Current vs Frequency
(squarewave).



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