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LM6172 Datasheet(PDF) 13 Page - National Semiconductor (TI) |
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LM6172 Datasheet(HTML) 13 Page - National Semiconductor (TI) |
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13 / 16 page ![]() Power Supply Bypassing (Continued) Termination In high frequency applications, reflections occur if signals are not properly terminated. Figure 6 shows a properly termi- nated signal while Figure 7 shows an improperly terminated signal. To minimize reflection, coaxial cable with matching charac- teristic impedance to the signal source should be used. The other end of the cable should be terminated with the same value terminator or resistor. For the commonly used cables, RG59 has 75 Ω characteristic impedance, and RG58 has 50 Ω characteristic impedance. Power Dissipation The maximum power allowed to dissipate in a device is de- fined as: P D = (TJ(max) −TA)/θJA Where P D is the power dissipation in a device T J(max) is the maximum junction temperature T A is the ambient temperature θ JA is the thermal resistance of a particular package For example, for the LM6172 in a SO-8 package, the maxi- mum power dissipation at 25˚C ambient temperature is 780 mW. Thermal resistance, θ JA, depends on parameters such as die size, package size and package material. The smaller the die size and package, the higher θ JA becomes. The 8-pin DIP package has a lower thermal resistance (95˚C/W) than that of 8-pin SO (160˚C/W). Therefore, for higher dissipation capability, use an 8-pin DIP package. The total power dissipated in a device can be calculated as: P D = PQ +PL P Q is the quiescent power dissipated in a device with no load connected at the output. P L is the power dissipated in the de- vice with a load connected at the output; it is not the power dissipated by the load. Furthermore, P Q: = supply current x total supply voltage with no load P L: = output current x (voltage difference between sup- ply voltage and output voltage of the same supply) For example, the total power dissipated by the LM6172 with V S = ±15V and both channels swinging output voltage of 10V into 1 k Ω is P D: = P Q +PL : = 2[(2.3 mA)(30V)] + 2[(10 mA)(15V − 10V)] : = 138 mW + 100 mW : = 238 mW DS012581-47 FIGURE 5. Power Supply Bypassing DS012581-53 FIGURE 6. Properly Terminated Signal DS012581-54 FIGURE 7. Improperly Terminated Signal www.national.com 13 |
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