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MAX42410 Datasheet(PDF) 13 Page - Analog Devices |
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MAX42410 Datasheet(HTML) 13 Page - Analog Devices |
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13 / 19 page ![]() MAX42408/MAX42410 36V, 8A/10A Fully Integrated Buck Converter with 10μA Quiescent Current and Dual-Phase Capability www.analog.com Analog Devices | 13 ESRIN = ∆VESR ILOAD(MAX) + ∆IL 2 ⁄ CIN = ILOAD(MAX) × D (1 − D) ∆VQ × fSW Where: ∆IL = ( VSUP − VOUT) × VOUT VSUP × fSW × L D = VOUT VSUP and ILOAD(MAX) is the maximum output current, ΔIL is peak-to-peak inductor current, fSW is switching frequency, and D is the duty cycle. Selecting the Inductor Inductor selection is a compromise between component size, efficiency, control loop bandwidth, and loop stability. Insufficient inductance increases the inductor current ripple, conduction losses, and output voltage ripple, and causes loop instability in the worst case. A large inductor reduces the inductor current ripple by sacrificing component size and slow response. For recommended inductor values, see Table 2. Output Capacitor The output capacitor is a critical component for switching regulators. It is selected to meet output voltage ripple, load transient response, and loop stability requirements. The output voltage ripple comprises ΔVQ (caused by the capacitor discharge) and ΔVESR (caused by the ESR of the output capacitor). Use low ESR ceramic capacitors. Assume the contribution to the output ripple voltage from ESR and the capacitor discharge to be equal. Use the following equations to get the output capacitance and ESR for a specified output voltage ripple. ESR = ∆VESR ∆IP-P COUT = ∆IP-P 8 × ∆VQ × fSW ∆IP-P = ( VSUP − VOUT) × VOUT VSUP × fSW × L VOUTRIPPLE = ∆VESR + ∆VQ Where, ΔIP-P is the peak-to-peak inductor current, and fSW is the switching frequency. During a load step, the output capacitors supply the load current before the converter loop responses with higher duty cycle, which causes output voltage undershoot. To keep the maximum output voltage deviations below the tolerable limits of the electronics being powered, calculate the output capacitance with the following equation: COUT = ∆ILOAD ∆V × 2π × fC Where, ΔI is the load step, ΔV is the allowed output voltage undershoot, and fC is the loop crossover frequency, which can be assumed to be the lesser of fSW/10 or 100kHz. The calculated COUT is the capacitance after considering capacitance tolerance, temperature effect, and voltage derating. Table 2 shows the recommended values of output capacitance based on frequency and output voltage. |
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